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VashaNatasha [74]

2 years ago

8

This table shows how many sophomores and juniors attend two high school events . what is the probability that a randomly chosen

person from this group is a sophomore? round your answer to two decimal places.

2 answers:

bearhunter [10]2 years ago

8 0

Answer:

0.26 is the answer

Alik [6]2 years ago

3 0

Answer:

i think its 0.56

Step-by-step explanation:

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Use the given data valuesâ (a sample of female arm circumferences inâ centimeters) to identify the corresponding z scores that a

tekilochka [14]

Answer:

The normal quantile plot is provided below.

Step-by-step explanation:

The standardized normal scores are known as <em>z</em>-scores.

If there are <em>n</em> values in a data set then the area corresponding to these <em>n</em> values is given by:

$\text{Area}=\frac{i-0.5}{n}$

Here, <em>i</em> € {1, 2, ..., n}.

Arrange the data provided in ascending order.

S = { 31.8, 34.8, 38.2, 40.3, 44.2}

Consider the table for the <em>z</em>-scores.

To form the normal quantile plot, make a scatter plot with the <em>z</em>-scores on the <em>y</em>-axis and the values provided on the <em>x-</em>axis.

The normal quantile plot is provided below.

8 0

2 years ago

The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"

svetlana [45]

Answer:

At least 202.44 mm in the top 15%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 134, \sigma = 66$

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.

$Z = \frac{X - \mu}{\sigma}$

$1.037 = \frac{X - 134}{66}$

$X - 134 = 66*1.037$

$X = 202.44$

At least 202.44 mm in the top 15%.

5 0

2 years ago

ΔABC underwent a sequence of rigid transformations to give ΔA′B′C′. Which transformations might have taken place?

Papessa [141]

Answer: The correct option is second, a rotation $90^{\circ}$ clockwise about the origin followed by a reflection across the x-axis.

Explanation:

From the given figure it is noticed that the vertices of ΔABC are A(-6,4), B(-4,6), C(-2,2) and vertices of ΔA'B'C' are A'(4,-6), B(6,-4), C(2,-2).

It means if the point is P(x,y) then after transformation it will be P'(y,x).

If a point P(x,y) reflection across the y-axis followed by a reflection across the x-axis, then the image of point after transformation will be P'(-x,-y), therefore it is not the correct option.

If a shape is rotated $90^{\circ}$ clockwise about the origin then the point P(x,y) will be P'(y,-x) and after that reflect across the x-axis, so the point after transformation will be P'(y,x), therefore it is the correct option.

If a shape is rotated $270^{\circ}$ clockwise about the origin then the point P(x,y) will be P'(-y,x) and after that reflect across the x-axis, so the point after transformation will be P'(-y,-x), therefore it is not the correct option.

If a point P(x,y) reflection across the x-axis followed by a reflection across the y-axis, then the image of point after transformation will be P'(-x,-y), therefore it is not the correct option.

Hence, the correct option is second, a rotation $90^{\circ}$ clockwise about the origin followed by a reflection across the x-axis.

4 0

2 years ago

Read 2 more answers

Using a 16-sided number cube, what is the probability that you will roll a multiple of 4 or an odd prime number? The number 1 is

iogann1982 [59]

<h3>Answer: 0.563 (choice C)</h3>

================================================

Explanation:

E = event space

E = set of outcomes we want to happen

E = rolling a multiple of 4 or rolling an odd prime number

E = {4,8,12,16 3,5,7,11,13}

n(E) = number of items in set E

n(E) = 9, (four multiples of 16+five ways to roll odd prime number)

-----

S = sample space

S = set of all possible outcomes (whether we want them to happen or not)

S = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}

n(S) = number of items in set S

n(S) = 16

-----

P(E) = probability of event space occurring

P(E) = probability of rolling a multiple of 4 or rolling an odd prime number

P(E) = n(E)/n(S)

P(E) = 9/16

P(E) = 0.5625

P(E) = 0.563

3 0

2 years ago

What value digit in 2,417 is ten times as value of the digit in 2,147

3241004551 [841]

Answer:

4 in 2,417

4 in 2,147

Step-by-step explanation:

the place value of 4 in 2,417 is HUNDREDS

while the place value of 4 in 2,147 is TENS

Therefore the place value of 4 in 2,417 is ten times the value of 4 in 2,147

3 0

2 years ago