Ask question

Ask question

All categories

2 years ago

12

Which sequence of transformations carries abcd onto efgh

1 answer:

Inessa [10]2 years ago

6 0

Answer:

D

Step-by-step explanation:

You might be interested in

A wild animal generally stays at least x mi from the edge of a forest. For a rectangular forest preserve that is 2 mi

Butoxors [25]

Answer:

$Area = 4x^2 - 14x + 10$

Step-by-step explanation:

<em>See Attachment for Complete Question</em>

Given

$Width = 5mi$ --- For the forest

$Length = 2mi$ -- --- For the forest

Required

Determine the area of the habitat

Since the distance between the animal's habitat is x mi on both sides;

The length and width of the habitat is:

$Width = 5 - (x + x)$

$Width = 5 - 2x$

$Height = 2 - (x +x)$

$Height = 2 - 2x$

The area is then calculated as follows;

$Area = Width * Height$

$Area = (5 - 2x) * (2 - 2x)$

Expand

$Area = 5(2 - 2x) -2x(2 - 2x)$

Open Brackets

$Area = 10 - 10x - 4x + 4x^2$

$Area = 10 - 14x + 4x^2$

Reorder

$Area = 4x^2 - 14x + 10$

Hence; the required polynomial for the habitat area is:

$Area = 4x^2 - 14x + 10$

3 0

2 years ago

Drew creates a table of ordered pairs representing the width and area of a dog pen. Which situation could describe Drew’s plans

Feliz [49]

Answer:

the answer is A :)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

−4x+60<72 or 14x+11<−31 solve for x

gulaghasi [49]

The answer to your question is x = 8

5 0

2 years ago

Read 2 more answers

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

2 years ago

Carmen draws this area model to help her divide 1,800 by 9. She says the quotient is 20

lisov135 [29]

Answer: the answer is 200

Step-by-step explanation:

6 0

2 years ago