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2 years ago

Bob works at a café, where he earns $11 an hour. Which of the following

Mathematics

1 answer:

kondor19780726 [428]2 years ago

4 0

Answer: The graph shown in picture is correct answer.

Step-by-step explanation: An equation for this is 11x=$ he makes where x represent hours.

In graph some points would be (0,0) (1,11) (2,22).... .

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C=wtc/1000 solve for w

Nutka1998 [239]

For this case we have the following equation:
$C = \frac{wtc}{1000}$
To clear w, we must follow the following steps:
1) The value of t multiplied by c pass to divide the other side of the equation:
$\frac{w}{1000} = \frac{C}{tc}$
2) the value of 1000 is passed to multiply to the other side of the equation:
$w = \frac{1000C}{tc}$
Answer:
The cleared equation for w is:
$w = \frac{1000C}{tc}$

3 0

2 years ago

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A 12-foot high ladder reaches a tree limb when it leans at a 36 degree angle with the ground. Approximately how far away is the

Allisa [31]

Look at the picture.

$\cos 36^\circ = \frac{x}{12} \\
0.809 \approx \frac{x}{12} \\
0.809 \times 12 \approx x \\
x \approx 9.708$

The base of the ladder is approximately 9.708 feet from the tree trunk base.

4 0

2 years ago

Gwen buys 3 identical pairs of shoes at Store a. She pays $110.25 after the discount. what is the original price of each pair?

emmasim [6.3K]

In perspective this looks tricky but really its no ;) just follow it slowly.
110.25 is your total cost
3 is how many you bought.
So doing division 3/110.25= 36.75
CHECK: 36.75 + 36.75 + 36.75 = 110.25.
Hope this helps.

5 0

2 years ago

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Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot

Anastasy [175]

Option B : $\frac{1}{\sqrt[3]{x^{5} } }$ is the expression equivalent to $x^{-\frac{5}{3}$

Explanation:

The given expression is $x^{-\frac{5}{3}$

Rewriting the expression $x^{-\frac{5}{3}$ using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

$\frac{1}{x^{\frac{5}{3} } }$

Simplifying, we get,

$\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}$

Applying the rule, $a^{\frac{1}{n}}=\sqrt[n]{a}$

Thus, we have,

$\frac{1}{\sqrt[3]{x^{5} } }$

Now, we shall determine from the options that which expression is equivalent to $x^{-\frac{5}{3}$

Option A: $\frac{1}{\sqrt[5]{x^{3} } }$

The expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option A is not the correct answer.

Option B: $\frac{1}{\sqrt[3]{x^{5} } }$

The expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to $x^{-\frac{5}{3}$

Hence, Option B is the correct answer.

Option C: $-\sqrt[3]{x^5}$

The expression $-\sqrt[3]{x^5}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[3]{x^5}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option C is not the correct answer.

Option D: $-\sqrt[5]{x^3}$

The expression $-\sqrt[5]{x^3}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[5]{x^3}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option D is not the correct answer.

4 0

2 years ago

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Four speed skaters, Marco, Naim, Oliver, and Pedro, compete in a relay race where they all agree that Naim will be the last

allochka39001 [22]

Answer:

A = {MOPN, MPON, PMON, POMN}

Step-by-step explanation:

Everyone has already agreed that Naim would be the last skater, so we have to make sure that the result has 'N' in each last place. As we can see, they all have this.

Now, we also have to make sure Oliver <u>not</u> first, because although they're trying to decide, the problem asks for the <u>complement</u> in which "Oliver is the first skater in the race."

A complement is all the values that are NOT in the set, so it cannot be A = {OPMN, OMPN) or A = {MOPN,MPON, OPMN, POMN), because they both have at least one case where 'O' is first.

A complement is ALL other values of the set, so it cannot be A = {MOPN, PMON}, because that set only shows two possible values.

Therefore, A = {MOPN, MPON, PMON, POMN} is your answer.

5 0

2 years ago

Read 2 more answers