Answer:
Due to the higher z-score, David has the higher standardized score
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Which student has the higher standardized score
Whoever had the higher z-score.
David:
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So 



Steven:
Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So 



Due to the higher z-score, David has the higher standardized score
Answer:
B. (1/2, 3)
Step-by-step explanation:
It is perhaps easiest to try the point values in the equations.
A — 4·2+1 = 9; -2·2 +4 ≠9 . . . . not the answer
B — 4·1/2 +1 = 3; -2·(1/2) +4 = 3 . . . . this is the answer
we need go no further since we have the answer
Answer:
60/220
Step-by-step explanation:
we use combination,


then, all divided by,


Answers:
A) △ACF ≅ △AEB because of ASA.
D) ∠CFA ≅ ∠EBA
E) FC ≅ BE
Solution:
AC ≅ AE; ∠ACD ≅ ∠AED Given
The angle ∠CAF ≅ ∠EAB, because is the same angle in Vertex A
Then △ACF ≅ △AEB because of ASA (Angle Side Angle): They have a congruent side (AC ≅ AE) and the two adjacent angles to this side are congruent too (∠ACD ≅ ∠AED and ∠CAF ≅ ∠EAB), then option A) is true: △ACF ≅ △AEB because of ASA.
If the two triangles are congruent, the ∠CFA ≅ ∠EBA; and FC ≅ BE, by CPCTC (Corresponding Parts of Congruent Triangles are Congruent), then Options D) ∠CFA ≅ ∠EBA and E) FC ≅ BE are true
Answer:
D. y+15 = 4/5(x+5)
Step-by-step explanation:
A line contains the points (8,9) and (-12, -7).
(y2 - y1) = m(x2 - x1)
(9 - (-7))= m (8 -(-12))
16 = m*20
m = 16/20 = 4/5
Given line has slope m= 4/5.
Parallel line has the same slope m = 4/5.
Point-slope equation is (y - y1) = m(x - x1).
We have slope m = 4/5, and point (-5, -15).
So,
(y - (-15)) = 4/5(x - (-5))
y+15 = 4/5(x+5)