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saveliy_v [14]
1 year ago
10

Jack bought seven tickets for a movie he paid seven dollars for each adult ticket and four dollars for each child ticket jack sp

end $40 for the ticket write a system of equations that will determine how many adult tickets jack bought (PLEASE HELP)
Mathematics
1 answer:
Alja [10]1 year ago
7 0

7x = 40

7x + 4y = 40

The first equation represents that in total, the 7 tickets whether they are for adults or children costs $40.

The second equation represents that x = adult and y = children tickets both add up to equal $40.

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Jim is building a rectangular deck and wants the length to be 1 ft greater than the width. what will be the dimensions of the de
Travka [436]
Let x = width
x+1 is then the length

2x+2(x+1)=66
2x+2x+2=66
4x=64
x=16
deck will be 16x17, nice for a BBQ. :)
3 0
1 year ago
I am factor of 12. The other factor is 3. What number am I
Goryan [66]
12*3= 36

12 and 3 could be factors of 36.

I hope this helped you! <3
8 0
1 year ago
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Given the functions f(x) = 7x + 13 and g(x) = x + 2, which of the following functions represents f[g(x)] correctly?
LenKa [72]

Answer:

B. f(g(x)) = 7x + 27

Step-by-step explanation:

We have, f(x) = 7x+13 and g(x) = x+2.

So, the function f(g(x)) is obtained by substituting the function g(x) = x+2 in f(x) = 7x+13,

i.e. f(g(x)) = f(x+2)

i.e. f(g(x)) = 7 × (x+2) + 13

i.e. f(g(x)) = 7x + 14 + 13

i.e. f(g(x)) = 7x + 27

Thus, f(g(x)) = 7x + 27

Hence, option B is correct.

4 0
2 years ago
Read 2 more answers
In equilateral ∆ABC with side a, the perpendicular to side AB at point B intersects extension of median AM in point P. What is t
Sergeeva-Olga [200]

Answer:

Perimeter  = (2 + √3)·a

Step-by-step explanation:

Given: ΔABC is equilateral and AB = a

The diagram is given below :

AM is a median , PB ⊥ AB , PM = b

Now, by using properties of equilateral triangle, median is perpendicular bisector and each angle is of 60°.

We get, ∠AMB = 90°. So, by linear pair ∠AMB + ∠PMB = 180° ⇒ ∠PMB = 90°. Also, ∠ABC = 60° and ∠ABP = 90° (given) So, ∠PBM = 30°

Since, AM is perpendicular bisector of BC. So,

MB = \frac{a}{2}

Now in ΔAMB , By using Pythagoras theorem

AB^{2}=AM^{2}+MB^{2}\\AM^{2}=AB^{2}-MB^{2}\\AM^{2}=a^{2}-(\frac{a}{2})^{2}\\AM=\frac{\sqrt{3}\cdot a}{2}

Now, in ΔBMP :

sin\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\sin\thinspace 30^{o}=\frac{\text{MB}}{\text{PB}}\\\\PB=\frac{\text{MB}}{\text{sin 30}}\\\\PB=\frac{\frac{a}{2}}{\frac{1}{2}}\implies PB = a\\\\tan\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Base}}\\\\tan\thinspace 30^{o}=\frac{\text{MB}}{\text{PM}}\\\\PM=\frac{\text{MB}}{\text{tan 30}}\\\\PM=\frac{\frac{a}{2}}{\frac{1}{\sqrt3}}\implies PM=b= \frac{\sqrt{3}\cdot a}{2}

Perimeter of ABM = AB + PB + PM + AM

\text{Perimeter = }a+a+b+ \frac{\sqrt{3}\cdot a}{2}\\\\=2\cdot a + \frac{\sqrt{3}\cdot a}{2} +\frac{\sqrt{3}\cdot a}{2}\\\\=2\cdot a +\sqrt{3}\cdot a\\\\=(2+\sqrt3})\cdot a

Hence, Perimeter of ΔABP = (2 + √3)·a units

3 0
1 year ago
Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and n
lana [24]
Let wind speed = x mph 

when she rode 2 miles against the wind we have:-
speed = distance / time so
20 - x  = 2 / t -------(1)      where t is the time she took.

when riding with the wind we have 

20 + x = 3 / t--------(2)   adding equations (1) and (2):-

40  =  2/t + 3/t
40 =  5/t
t = 5/40 = 1/8 hr 

x = 20 - 2 / 1/8  = 20 - 16 = 4

Wind speed was 4 mph Answer

4 0
2 years ago
Read 2 more answers
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