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Tems11 [23]
2 years ago
11

The graphic shows the citric acid cycle. A diagram of the citric acid cycle is shown. Acetyl C o A enters the citric acid cycle

and combines with a 4-carbon compound to form citric acid. During the citric acid cycle, what happens to acetyl-CoA? It enters the citric acid cycle and gains carbon dioxide to form citric acid, and gains more carbon dioxide through redox reactions to form a 4-carbon molecule. It enters the citric acid cycle and associates with a 4-carbon molecule, forming citric acid, and then through redox reactions regenerates the 4-carbon molecule. It enters glycolysis and associates with a 5-carbon molecule through redox reactions, forming another acetyl-CoA molecule. It enters the citric acid cycle and associates with a 4-carbon molecule, forming a 5-carbon compound, and then through oxidation reactions regenerates the 4-carbon molecule.
Biology
2 answers:
pychu [463]2 years ago
7 0

Answer:

the answer is b

Explanation:

i just did it on edge

make me brainliest :)

vagabundo [1.1K]2 years ago
3 0

Answer:

It enters the citric acid cycle and associates with a 4-carbon molecule, forming citric acid, and then through redox reactions regenerates the 4-carbon molecule.

Explanation:

Acetyl-CoA(2C) associates with oxalacetate(4C) to form citric acid(6C). Then through redox reactions, CO2 molecules result from decarboxylation (COOH becomes R-(R1)CH-R2). And through dehydrogenation H2 molecules are incorporated in NADH+ in FADH2, resulting in the 4-carbon molecule at the beginning (oxalacetate). That's why it's called a cycle(Kreb's cycle or citric acid cycle)

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Answer:

Because DNA polymerase can synthesize DNA strands in 5' to 3' direction only.

Explanation:

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Therefore, the lagging strand is synthesized discontinuously in the form of short DNA fragments. These are called Okazaki fragments. Primers are formed for short distances which in turn are elongated by DNA polymerase to form the Okazaki fragments. On the other hand, the synthesis of the leading strand occurs continuously in the same direction in which the replication fork moves.

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Answer:

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