First, we are going to find the sum of their age. To do that we are going to add the age of Eli, the age Freda, and the age of <span>Geoff:
</span>

The combined age of Eli, Freda, and Geoff is 40, so the denominator of each ratio will be 40.
Next, we are going to multiply the ratio between the age of the person and their combined age by <span>£800:
For Eli: </span>
For Freda:
For Geoff: 
<span>
We can conclude that
Eli will get </span>
£180,
Freda will get £260, and
Geoff will get <span>
£360.</span>
Answer:
280 people
Step-by-step explanation:
Given that 65% of people surveyed were pleased with condition of the park.
Given that those pleased were 182 people, then finding the total number of people surveyed will be;
65%= 182 people
100%= ?--------------------cross multiply

Answer:
The value of the parameter is λ is 0.03692
Step-by-step explanation:
Consider the provided function.
for −∞ < x < ∞.
It is given that standard deviation is given as 38.3 km.
Now we need to calculate the value of parameter λ.
The general formula for the probability density function of the double exponential distribution is: 
Where μ is the location parameter and β is the scale parameter.
Compare the provided equation with the above formula we get.
and μ = 0.
Standard deviation = √2β

Now substitute the value of β in
.

Hence, the value of the parameter is λ is 0.03692
Answer:
![f(x)=4\sqrt[3]{16}^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D)
Step-by-step explanation:
We believe you're wanting to find a function with an equivalent base of ...
![4\sqrt[3]{4}\approx 6.3496](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B4%7D%5Capprox%206.3496)
The functions you're looking at seem to be ...
![f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x](https://tex.z-dn.net/?f=f%28x%29%3D2%5Csqrt%5B3%5D%7B16%7D%5Ex%5Capprox%202%5Ccdot2.5198%5Ex%5C%5C%5C%5Cf%28x%29%3D2%5Csqrt%5B3%5D%7B64%7D%5Ex%3D2%5Ccdot%204%5Ex%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D%5Capprox%204%5Ccdot%206.3496%5Ex%5C%20%5Cleftarrow%5Ctext%7B%20this%20one%7D%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B64%7D%5E%7B2x%7D%3D4%5Ccdot%2016%5Ex)
The third choice seems to be the one you're looking for.