Question

Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript x f(x) = 2(RootIndex 3 StartRoot 64 EndRoot) Superscript x f(x) = 4(RootIndex 3 StartRoot 16 EndRoot) Superscript 2 x f(x) = 4(RootIndex 3 StartRoot 64 EndRoot) Superscript 2 x

Answer 1

Answer:

  $f(x)=4\sqrt[3]{16}^{2x}$

Step-by-step explanation:

We believe you're wanting to find a function with an equivalent base of ...

  $4\sqrt[3]{4}\approx 6.3496$

The functions you're looking at seem to be ...

  $f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x$

The third choice seems to be the one you're looking for.

Answer 2

Answer:look at the pic

Step-by-step explanation: