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Tresset [83]
2 years ago
5

Krzysztof solved the quadratic equation $11x^2-44x-99=0$ by completing the square. In the process, he came up with the equivalen

t equation (x+r)^2 = s, where $r$ and $s$ are constants. What is $r+s$?
Mathematics
1 answer:
lys-0071 [83]2 years ago
3 0

Answer:

r = -2

s = 13

Step-by-step explanation:

Given quadratic equation is,

11x² - 44x - 99 = 0

Divide this equation by 11,

x² - 4x - 9 = 0

x² - 2(2)x - 9 = 0

x² -2(2)x + 2² - 2² - 9 = 0

[x² - 2(2)x + 2²] - 4- 9 = 0

(x - 2)² - 13 = 0

(x - 2)² = 13

[x + (-2)]² = 13

By comparing this equation with  (x + r)² = s

Values of the constants r and s will be,

r = (-2) and s = 13

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AfilCa [17]

Answer:

In case (a) car makes 105° turn.

In case (b) car makes 75° turn.

In case (c) car makes 105° turn.

Step-by-step explanation:

Figure is redrawn To explain properly (in attachment)

Given : streets are parallel means \overline{AB} ║ \overline{CD},

             AB - 4th street , CD - 3rd street and XY - King Ave.

            ∠XLA = 75°

To find : (a) ∠XLB

              (b) ∠LMD (left onto 3rd streat means left of car)

              (c) ∠YMD (right means right side of car)

∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are  

                                     supplementary)

∠XLB + 75° = 180°

∠XLB  = 180 - 75

∠XLB = 105°

∴ In case (a) car makes 105° turn.

∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)

∠LMD = 75°

∴ In case (b) car makes 75° turn.

∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are

                                       supplementary)

∠YMD + 75° = 180°

∠YMD = 180 - 75

∠YMD = 105°

∴In case (c) car makes 105° turn.

8 0
2 years ago
On a test, leo is asked to completely factor the polynomial 3x3 – 3x 5x2 – 5. he uses double grouping to get (x2 – 1)(3x 5). has
Agata [3.3K]

No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get

(x – 1)(x + 1)(3x + 5).

8 0
2 years ago
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4 and 5 are complements, and 1 and 5 are complements. By the congruent complements theorem, which angle is congruent to 4? 1 2 3
Zepler [3.9K]
The theorem tells you angles complementary to the same angle are congruent. Both 4 and 1 are complementary to 5, so 4 and 1 are congruent.

The angle congruent to 4 is 1.
8 0
2 years ago
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As a smart consumer, you are always on the lookout for sales, coupons, and rebates. While shopping for new clothes, you notice t
Firlakuza [10]

Answer:

You'd have to buy 3 shirts in order to use your coupon.

Step-by-step explanation:

Each shirt originally costs $17.99

One particular brand of shirts is on sale for 20% off the original price.

$17.99*0.2= $3.60 (amount taken off for each shirt)

Now subtract $3.60 from $17.99.

$17.99 - $3.60 = $14.39 (per shirt)

40 / 14.39 = 2.779 (round to 3)

You'd have to buy 3 shirts in order to use your coupon.

$14.39 * 3 = $43.17, in order to get $10 off you'd need to spend at least $40

7 0
2 years ago
Members of the pep club were selling raffle tickets for $1.50 and $5. The number of $1.50 tickets sold was two less than four ti
marysya [2.9K]

Answer:

see below

Step-by-step explanation:

1.5x + 5y = 1152    

x = 4y – 2

We can substitute the second equation into the first equation

Which one-variable linear equation can be formed using the substitution method?

1.5(4y-2) +5y = 1152  

Distribute

6y -3 +5y = 1152

Combine like terms

11y-3 = 1152

Add 3 to each side

11y-3+3 = 1152+3

11y = 1155

Divide each side by 11

11y/11 = 1155/11

y = 105

How many $5 raffle tickets were sold?

105 5 dollar tickets were sold

Now we need to find the number of 1.50 tickets

Which equation can be used to determine how many $1.50 raffle tickets were sold?

x = 4y – 2

x = 4(105) -2

   =420-2

   = 418

How many $1.50 raffle tickets were sold?

418    $1.50 tickets were sold

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2 years ago
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