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Monica [59]
2 years ago
3

In the diagram, StartFraction V Z Over Y Z EndFraction = StartFraction W Z Over X Z EndFraction. Triangles V W Z and Y X Z are c

onnected at point Z. To prove that △VWZ ~ △YXZ by the SAS similarity theorem, which other sides or angles should be used? WV and XY WV and ZY ∠VZW ≅ ∠YZX ∠VWZ ≅ ∠YXZ
Mathematics
1 answer:
marshall27 [118]2 years ago
5 0

Answer:

Option C.

Step-by-step explanation:

It is given that

\dfrac{VZ}{YZ}=\dfrac{WZ}{XZ}

Triangles VWZ and YXZ are connected at point Z.  

According to SAS similarity theorem, two triangles are similar if two corresponding sides are proportional and the angles between proportional sides are equal.

To prove that △VWZ ~ △YXZ by the SAS similarity theorem, we have two corresponding proportional sides nd we need to find the angle between proportional sides.

In △VWZ and △YXZ, VZ and YZ, WZ and XZ are corresponding angles which are proportional.

Angle between VZ and WZ is ∠VZW.

Angle between YZ and XZ is ∠YZX.

So, △VWZ ~ △YXZ by the SAS similarity theorem if ∠VZW ≅ ∠YZX.

Therefore, the correct option is C.

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Angle AOE has what measurement according to the protractor?
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Answer:120

Step-by-step explanation:

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2 years ago
A population consists of the following five values: 1, 3, 4, 4, and 6. List all samples of size 2 from left to right without rep
aniked [119]

Answer:

The sample of sizes 2 and their mean are given below.

Step-by-step explanation:

The population consist of  5 values, S = {1, 3, 4, 4, 6}.

The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

{5\choose 2}=\frac{5!}{2!(5-2)!} =10

Th formula to compute the mean is:

\bar x=\frac{1}{n}\sum x_{i}

List the 10 samples and their mean as follows:

<u>Sample</u>                       <u>Mean</u>

(1, 3)                    \bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 6)                    \bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 6)                   \bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5

(4, 4)                   \bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

8 0
2 years ago
Jake made a total of 7 copies at a copy shop, with some being black-and-white copies and some being color copies. Black-and-whit
Arada [10]
Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents

70 = 8b + 15c

he made a total of 7 copies
b + c = 7

system of equation:
70 = 8b + 15c
b + c = 7

--------------------------

b + c = 7
b + c (-c) = 7 (-c)
b = 7 - c

plug in 7 - c for b

70 = 8(7 - c) + 15c
Distribute the 8 to both 7 and - c (distributive property)

70 = 56 - 8c + 15c
Simplify like terms

70 = 56 - 8c + 15c
70 = 56 + 7c

Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides

70 (-56) = 56 (-56) + 7c
14 = 7c

divide 7 from both sides to isolate the c

14 = 7c
14/7 = 7c/7
 c = 14/7
 c = 2

c = 2
---------------

Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
c = 2
<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
b + 2 (-2) = 7 (-2)
b = 7 - 2
b = 5

Jake made 5 black-and-white copies, and 2 color copies

hope this helps
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