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Anettt [7]
2 years ago
13

Leo is constructing a tangent line from point Q to circle P. What is his next step? circle P and point Q on the outside of circl

e P, a segment is created from points P and Q, a set of arcs are created from point P above and below segment PQ that are greater than half the distance of segment PQ, another set of arcs are created from point Q above and below segment PQ that are greater than half the distance of segment PQ, the intersections of the created arcs are connected with a line creating point R on segment PQ Construct a circle from point Q with the radius PR. Construct the perpendicular bisector of segment PQ. Construct a circle from point R with the radius RP. Construct the perpendicular bisector of segment RQ.

Mathematics
1 answer:
xxMikexx [17]2 years ago
3 0

Answer:

The correct option is;

Construct a circle from point R with the radius RP

Step-by-step explanation:

To draw a tangent, the following steps are required

1) A line is drawn connecting the point to the center of the circle to which the tangent is to be drawn

2) The perpendicular bisector of the line constructed to get the mid point of the line

3) From the midpoint of the line found in the step above the compass is adjusted to reach the center of the given circle and a circular arc is drawn across the circumference of the given circle

4) The point of intersection of the arcs and the circumference of the given circle are the tangent points

Therefore, the correct option is to construct a circle from point R with the radius RP.

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Paul is going to have the exterior of his home painted. Painting USA charges $75.00 to come out and evaluate the house plus $25.
murzikaleks [220]
CP - the cost of painting the house for Painting USA company [$]
cP = 75 + 25 * 25 = 75 + 625 = 700 [$]
cU - the cost of painting the house for Upscale Home Painting company [$]
cU = 0 + 40 * 25 = 1000 [$]

cP < cU
The most cost effective is Painting USA company.

n - number of houres required to paint the house if the same cost for both companies
75 + 25 * n = 40 * n
40 n - 25n = 75
15n = 75  /:15
n = 5
The cost of paining the house is the same for both companies if the number of houres required to paint the house is 5.


6 0
2 years ago
Scientists released 10 birds into a new habitat in year 0. Each year, there were
Natali [406]

Answer:

f(x) = 3^{x} + 10

Step-by-step explanation:

Year one would be 10 + 3

Year two would be (3*3)+10

year three would be (3*3*3)+10

Which easily simplifies into 3^{x} + 10.

8 0
2 years ago
Read 2 more answers
in 1990 automobile dealership sold certain model car for $14 and 649 cents in 2000 so the same model car for $23 and 609 cents f
Virty [35]
The original prize: 14.649

New prize: 23.609

(the years here are not relevant, just to confuse you with more numbers)

the increase is 23.609-14.649=8.960

If we want to know the percentage, we need to know what percentage of the original prize is 8.960.

this  is calculated like this:

\frac{8960}{14609}= 0.61164

ti make it into percentage, we multiply by 100%: 61.164%
3 0
1 year ago
A wagon can hold 44 pounds. A newspaper weighs 22 ounces. How many newspapers can the wagon hold?
miss Akunina [59]

Answer:

The wagon can hold 32 newspapers

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
Use the geometric definition of the cross product and the properties of the cross product to make the following calculations. (a
kirill [66]

Answer:

Step-by-step explanation:

we know

\vec{i}\times \vec{j}=\vec{k}

\vec{j}\times \vec{k}=\vec{i}

\vec{k}\times \vec{i}=\vec{j}

(a)\left [ \left ( \hat{i}+\hat{j}\right )\times \hat{i}\right ]\times \hat{j}

=\left [ \hat{i}\times \hat{i}+\hat{j}\times \hat{i}\right ]\times \hat{j}

=\left [ 0-\hat{k}\right ]\times \hat{j}

=\hat{i}

(b)\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{j}\times \hat{k}\right )

=\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{i}\right )

=\hat{k}+\hat{j}

(c)4\hat{i}\times \left ( \hat{i}+\hat{j}\right )

=4\hat{i}\times \hat{i}+4\hat{i}\times \hat{j}

=0+4\hat{k}

(d)\left ( \hat{k}+\hat{j}\right )\times \left ( \hat{k}-\hat{j}\right )

=\hat{k}\times \hat{k}-\hat{k}\times \hat{j}+\hat{j}\times \hat{k}-\hat{j}\times \hat{j}

=0+\hat{i}+\hat{i}-0

=2\hat{i}

6 0
2 years ago
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