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Anettt [7]
1 year ago
13

Leo is constructing a tangent line from point Q to circle P. What is his next step? circle P and point Q on the outside of circl

e P, a segment is created from points P and Q, a set of arcs are created from point P above and below segment PQ that are greater than half the distance of segment PQ, another set of arcs are created from point Q above and below segment PQ that are greater than half the distance of segment PQ, the intersections of the created arcs are connected with a line creating point R on segment PQ Construct a circle from point Q with the radius PR. Construct the perpendicular bisector of segment PQ. Construct a circle from point R with the radius RP. Construct the perpendicular bisector of segment RQ.

Mathematics
1 answer:
xxMikexx [17]1 year ago
3 0

Answer:

The correct option is;

Construct a circle from point R with the radius RP

Step-by-step explanation:

To draw a tangent, the following steps are required

1) A line is drawn connecting the point to the center of the circle to which the tangent is to be drawn

2) The perpendicular bisector of the line constructed to get the mid point of the line

3) From the midpoint of the line found in the step above the compass is adjusted to reach the center of the given circle and a circular arc is drawn across the circumference of the given circle

4) The point of intersection of the arcs and the circumference of the given circle are the tangent points

Therefore, the correct option is to construct a circle from point R with the radius RP.

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---------------------------------------------------------

Explanation:

To shift the graph 10 units to the left, we replace x with x+10. What's really going on is that the xy axis shifts 10 units to the right (because x is now x+10; eg, x = 2 ---> x+10 = 2+10 = 12) so it appears that the graph is moving to the left. The general rule is h(x) = g(x+10). 

So,
g(x) = |x|
g(x+10) = |x+10| ... every x has been replaced with x+10
h(x) = g(x+10)
h(x) = |x+10|

We can use a graphing tool like GeoGebra to visually confirm we have the right answer (see attached). Note how a point like (0,0) on the green graph moves to (-10,0) on the red graph. 

7 0
1 year ago
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Mandy used the input and output in this table to write ratios. She concluded that because they are not all equivalent, this is n
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Answer:

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Answer:

[1250,1350).

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

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i.e., 1250\leq x\leq 1300     ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

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1350 is not included in the error interval for x.​

Interval notation is [1250,1350).

Therefore, the error interval for x is [1250,1350).

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