Answer:
$311.74
Step-by-step explanation:
A financial calculator computes the payment amount to be $311.74.
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Your graphing calculator may have the capability to do this. Certainly, such calculators are available in spreadsheet programs and on the web.
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The appropriate formula is the one for the sum of terms of a geometric series.
Sn = a1·((1+r)^n -1)/(r) . . . . . where r is the monthly interest rate (0.005) and n is the number of payments (480). Filling in the given numbers, you have ...
$620827.46 = a1·(1.005^480 -1)/.005 = 1991.4907·a1
Then ...
$620827.46/1991.4907 = a1 ≈ $311.74
what's up
Seek understand, to be understood!
To get the answer we need the formula or source.
The question in another way if 4cm=1.2km, what is the 10cm=--------
first, you have to use the crisscross.
4cm=1.2km
10cm= x it is variable
then, 4xx= 1.2kmx10cm
4x=12km
4x/4= 12/4
x=3km
Answer:
Given Polynomial:
Factors of Coefficient of terms
80 = 5 × 16
32 = 2 × 16
48 = 3 × 16
Common factor of the coefficient of all term is 16.
Each term contain variable. So the Minimum power of b is common from all terms.
Common from all variable part comes b².
So, Common factor of the polynomial = 16b²
⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )
⇒ 16b² ( 5b² - 2c³ + 3b²c )
Therefore, Statements that are true about David's word are:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property
Use different conversion factor to accomplish the task given above,
a. (78.9x10^-13 g) x (1 x 10^12 picogram/ 1 gram) = 7.89 pg
b. (6.41x10^-10 L) x (1 x 10^9 nanoliter / 1 L) = 0.641 nL
c. (3.15x10^11 m) x ( 1 x 10^-12 terameter / 1 meter) = Tm
d. (80 x10^-19) x (1 x10^18 atto / 1) = 8 atto
Given:
There are 4 quarts in a gallon.
She wants to convert 6 quarts to a gallon.
To find:
Whether she should multiply 6 by 4 or divide 6 by 4 to find her answer.
Solution:
We have,
Here, 6 quarts is equal to 
gallon. It means we need to multiply 6 by 4 in to find the answer.
