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Citrus2011 [14]
2 years ago
14

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)? StartFraction 3

(6) minus 1 Over 2 (6) + 1 EndFraction StartFraction (6) Over 2 (6) + 1 EndFraction StartFraction 36 minus 1 Over 26 + 1 EndFraction StartFraction (6) minus 1 Over (6) + 1 EndFraction
Mathematics
2 answers:
kolbaska11 [484]2 years ago
8 0

Answer:

A

Step-by-step explanation:

edg 2020

Misha Larkins [42]2 years ago
4 0

Answer:

  \dfrac{3(6)-1}{2(6)+1}

Step-by-step explanation:

For ...

  • r(x) = 3x -1  
  • s(x) = 2x +1

The expression (r/s)(6) is ...

  \left(\dfrac{r}{s}\right)(6) = \left.\dfrac{3x-1}{2x+1}\right|_{x=6}=\boxed{\dfrac{3(6)-1}{2(6)+1}}

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Step-by-step explanation:

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In Δ QRS:

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Learn more:

You can learn more about the trigonometry ratios in brainly.com/question/9880052

#LearnwithBrainly

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