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frez [133]
2 years ago
10

An airplane is traveling at a speed of 200 miles/hour with a bearing of 240°. The wind velocity is 60 miles/hour at a bearing of

25°. What are the plane's actual speed and direction angle?
Mathematics
1 answer:
Kisachek [45]2 years ago
4 0

This is a vector problem so we will split it by components and add them.


x direction

200sin(240) + 60sin(25) = -147.847985


y direction

200cos(240) + 60cos(25) = -45.6215327


To find the actual speed we now find the magnitude

(-147.847985)^2 + (-45.6215327)^2 = c^2


c = 154.72669748 mph


To find the direction we can do arctan of the different directions:

arctan(-147.847985/-45.6215327) = 252.85 degrees.


So the plane is going 154.73 mph at 252.85 degrees :)

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Answer:

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Step-by-step explanation:

Since the interest is calculated on the new balance every year.

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200 is the initial balance and Since, here the $15 is added to the balance each year. Therefore, P = 200+15t

r = rate each year (0.02)

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Therefore, the recursive formula is:

A(t) = 200+15t(1+0.02)^{t}

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Answer:

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1.6% should be your answer
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108 divided by 9 = 12 x -12 = -144 divided by 6 = -24 - (100 divided by 5) =

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Answer:

see below

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64 - 27 =37

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