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Anon25 [30]
2 years ago
10

For every 5 pages in a book Fred reads, Lonnie reads 4 pages. In 1 hour, they read a combined total of 36 pages. How many pages

did Lonnie read?
Mathematics
1 answer:
nydimaria [60]2 years ago
3 0

Answer:

Hence the number of pages read by Lonnie is 16 pages when they read a combined of 36 pages.

Step-by-step explanation:

The table that can be formed by the rate at which they study the number of pages of a book is:

Fred     Lonnie       total

 5           4                9

 10          8               18

 15          12              27

 20         16              36

That means when they read a combined of 36 pages.

Then the number of pages read by Fred is 20 pages.

and the number of pages read by Lonnie is 16 pages.

(

Also it could be done as :

Let Fred reads 'x' pages.

so, the number of pages read by Lonnie is: (4/5)x

Hence,

x+(4/5)x=36

on solving this linear equation we have:

x=20

and (4/5)x=16

)

Hence the number of pages read by Lonnie is 16 pages when they read a combined of 36 pages.

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Answer:

2n.2p.3r

Step-by-step explanation:

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2 years ago
What is the product of a+3 and −2a2+15a+6b2?
rewona [7]

For this case we must find the product of the following expression:

(a + 3) (- 2a ^ 2 + 15a + 6b ^ 2)

We apply distributive property term to term:

(a + 3) (- 2a ^ 2 + 15a + 6b ^ 2) =\\-2a ^ 2 * a + 15a * a + 6b ^ 2 * a-6a ^ 2 + 45a + 18b ^ 2 =\\-2a ^ 3 + 15a ^ 2 + 6ab ^ 2-6a ^ 2 + 45a + 18b ^ 2=

We add similar terms:

-2a ^ 3 + (15-6) a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2 =\\-2a ^ 3 + 9a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2 =

Finally, the expression is as:

-2a ^ 3 + 9a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2

Answeer:

-2a ^ 3 + 9a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2

5 0
2 years ago
Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres
liraira [26]

Answer:

P\left(8\right)=0

Step-by-step explanation:

Assuming that a fair die is rolled.

  • The sample space is 1, 2, 3, 4, 5, 6 and all the outcomes are equally likely.

Let  X  be the set of all possible outcomes. Let  A  be an outcome.

So, the probability that  A  occurs is:

                                                        P\left(A\right)=\frac{|A|}{|X|}

As the set of all possible outcomes of the roll of a single die is:

X=\left\{1,2,3,4,5,6\right\}

Observe that

|X|=6

Here  

|A|=0   because 8 is not in the set sample space. So, the outcome of occurring the number 8 is not possible from the all possible outcomes.

So, the probability must be zero.

In other words,

                        P\left(A\right)=\frac{|A|}{|X|}

                         P\left(8\right)=\frac{0}{6}=0

Therefore,

                   P\left(8\right)=0

5 0
2 years ago
Billy buys light bulbs in packs of 8 for $20. The shipping cost is $10 regardless of the number of packs bought. Billy has only
kirill115 [55]

Answer:

5

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7 0
2 years ago
Read 2 more answers
A circular platform is to be built in a playground. The center of the structure is required to be equidistant from three support
castortr0y [4]

Answer:

The coordinates for the location of the center of the platform are (0, 1)

Step-by-step explanation:

The equation of the circle of center (h , k) and radius r is:

(x - h)² + (y - k)² = r²

Now,

- The center is equidistant from any point lies on the circumference of the circle

- There are three points equidistant from the center of the circle

- We have three unknowns in the equation of the circle h , k , r

Thus, let's substitute the coordinates of these point in the equation of the circle to find h , k , r.

The equation of the circle is (x - h)² + (y - k)² = r²

∵ Points A(2,−3), B(4,3), and C(−2,5)

- Substitute the values of x and y the coordinates of these points

Point A (2 , -3)

(2 - h)² + (-3 - k)² = r² - - - (1)

Point B (4 , 3)

(4 - h)² + (3 - k)² = r² - - - - (2)

Point C (-2 , 5)

(-2 - h)² + (5 - k)² = r² - - - - (3)

- To find h , k equate equation (1) and (2) and same for equation (2) and (3) because all of them equal r²

Thus;

(2 - h)² + (-3 - k)² = (4 - h)² + (3 - k)² - - - - - (4)

(4 - h)² + (3 - k)² = (-2 - h)² + (5 - k)² - - - - -(5)

- Simplify (5);

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h² and k² will cancel out to give;

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Rearranging, we have;

12h - 4k = -4 - - - - (6)

Similarly, for equation 4;

(2 - h)² + (-3 - k)² = (4 - h)² + (3 - k)²

h² - 4h + 4 + k² + 6k + 9 = h² - 8h + 16 + k² - 6k + 9

h², k² and 9 will cancel out to give;

4 - 4h + 6k = 16 - 8h - 6k

Rearranging;

4h + 12k = 12 - - - - (7)

Divide by 4 to give;

h + 3k = 3

Making h the subject;

h = 3 - 3k

Put 3 - 3k for h in eq 6;

12(3 - 3k) - 4k = -4

36 - 36k - 4k = -4

40k = 40

k = 40/40

k = 1

h = 3 - 3(1)

h = 0

The coordinates for the location of the center of the platform are (0, 1)

5 0
2 years ago
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