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Anon25 [30]
2 years ago
13

N the diagram below, points $A,$ $E,$ and $F$ lie on the same line. If $ABCDE$ is a regular pentagon, and $\angle EFD=90^\circ$,

then how many degrees are in the measure of $\angle FDE$?
[asy]
size(5.5cm);
pair cis(real magni, real argu) { return (magni*cos(argu*pi/180),magni*sin(argu*pi/180)); }

pair a=cis(1,144); pair b=cis(1,72); pair c=cis(1,0); pair d=cis(1,288); pair e=cis(1,216);
pair f=e-(0,2*sin(pi/5)*sin(pi/10));
dot(a); dot(b); dot(c); dot(d); dot(e); dot(f);
label("$A$",a,WNW);
label("$B$",b,ENE);
label("$C$",c,E);
label("$D$",d,ESE);
label("$E$",e,W);
label("$F$",f,WSW);
draw(d--f--a--b--c--d--e);
draw(f+(0,0.1)--f+(0.1,0.1)--f+(0.1,0));
[/asy]
Mathematics
1 answer:
Cerrena [4.2K]2 years ago
7 0

Answer:

:0000000000000000000000

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velikii [3]
Strange problem...
Constraints are Y <= 40 bags and X=Y in quantity. Nothing else matters.  That's a bad decision unless the chicken farmer lost a poker hand to store X.

4 0
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Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4
Grace [21]
Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

C(n,r)= \frac{n!}{r!(n-r)!}

where n is a total number of choices ( 11 ) 
and r is number chosen out of those choices (4)
 so

C(11,4)= \frac{11!}{4!(11-4)!} 

She has 330 possible choices  to come home with 4 pieces of jewelry



5 0
2 years ago
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A wild animal generally stays at least x mi from the edge of a forest. For a rectangular forest preserve that is 2 mi
Butoxors [25]

Answer:

Area = 4x^2 - 14x + 10

Step-by-step explanation:

<em>See Attachment for Complete Question</em>

Given

Width = 5mi --- For the forest

Length = 2mi -- --- For the forest

Required

Determine the area of the habitat

Since the distance between the animal's habitat is x mi on both sides;

The length and width of the habitat is:

Width = 5 - (x + x)

Width = 5 - 2x

Height = 2 - (x +x)

Height = 2 - 2x

The area is then calculated as follows;

Area = Width * Height

Area = (5 - 2x) * (2 - 2x)

Expand

Area = 5(2 - 2x) -2x(2 - 2x)

Open Brackets

Area = 10 - 10x - 4x + 4x^2

Area = 10 - 14x + 4x^2

Reorder

Area = 4x^2 - 14x + 10

Hence; the required polynomial for the habitat area is:

Area = 4x^2 - 14x + 10

3 0
2 years ago
The perimeter of a pool table is about 7.8m. four times the length equals nine times the width. What are the dimensions of the t
Nana76 [90]

The pool's dimension are  l = 2.7 m and w = 1.2 m

Step-by-step explanation:

Step 1 :

Given

The pool's perimeter = 7.8 m

Four times the pool's length = nine times the pool's width.

=> 4l = 9w  => l = (\frac{9}{4}) w

Where l is the pool's length and w is the pool's width

Step 2:

The rectangle's formula for perimeter is 2 (l+w)

Substituting l = (\frac{9}{4}) w ,

2[ (\frac{9}{4}) w + w]  = 7.8 (given)

(\frac{13}{2}) w  = 7.8 = > w = 1.2 m

Step 3 :

l = (\frac{9}{4}) w = (\frac{9}{4}) 1.2 = 2.7

l = 2.7 m

Step 4 :

Answer :

The pool's dimension are  l = 2.7 m and w = 1.2 m

6 0
2 years ago
Q. If heights of 3rd graders follow a normal distribution with a mean of 52 inches and a standard deviation of 2.5 inches, what
zaharov [31]

Answer:

-2

Step-by-step explanation:

3 0
2 years ago
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