Answer:
No
Step-by-step explanation:
0.26*16 + 12.25 = 16.41
16.41 < 16.50
Answer:
The absolute brightness of the Cepheid star after a period of 45 days is -5.95
Step-by-step explanation:
Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by
M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.
From our question, it is given that P = 45 days.
So, M = –2.78(log P) – 1.35
M = –2.78(log 45) – 1.35
M = –2.78(1.6532) – 1.35
M = -4.60 - 1.35
M = -5.95
So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95
18 pears subtract by 2 wich will equal 16 pears...
18-2=16
Answer:
Not enough information
Step-by-step explanation:
one of the catapults could have more force than the other
