You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal
all $12$ cards at random to four players, so that each player gets three cards. What is the probability that each player gets an Ace, a $2$, and a $3$?
1 answer:
Answer:
Probability each player gets an ace, a $2 and a $3 = 0.0374
Step-by-step explanation:
The total number of ways to divide the card in triples among four players = 369600 ways
The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways
Probability each player gets an ace, a $2 and a $3 = 13824/369600
Probability each player gets an ace a $2 and a $3 = 0.0374
Note: Further explanation is provided in the attachment.
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Answer:
Step-by-step explanation:
We want to find h and k in:
At the inflection point, the second derivative is equal to zero, so:
Then x - h = 0.
Inflection point is located at (1, -2), replacing this x value we get:
1 - h = 0
h = 1
We know that the point (-2.5, -3.5) belongs to the function, so:
k ≈ -2
All data, used or not, are shown in the picture attached.
In this question , we have to simplify the given ratio, which is
12xy:3x
First we have to see which factor is common in numerator and denominator,
We can write 12 as 3 times 4, that is
So the common factor is 3x.
In the next step, we cancel out 3x
And that's the required simplified form .