Answer:
Find the five number summary of the data:
Minimum = x
Quartile 1 = x
Quartile 2 (median) = x
Quartile 3 = x
Maximum = x
Then, make the plot based on that information. If you are provided with a list of data, you should be able to use a calculator to find out that information.
<span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
= </span><span>8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4
= </span>8r^6s^3 – 9r^5s^4 + 4r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6
= 8r^6s^3 – 5r^5s^4 + r^4s^5 + 5r^3s^6
Hope it helps
(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.
Answer: D. 41 cm
There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,
a^2+b^2 = (b+1)^2
a^2 + b^2 = b^2 + 2b +1
a^2=2b+1
So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.
b = (a^2 - 1)/2
a=3, b=(3^2-1)/2=4, c=b+1=5
a=5, b=(5^2-1)/2 =12, c = 13
a=7, b=24, c=25
a=9, b=40, c=41
a=11, b=60, c=61
a=13, b=84, c=85
It's good to be able to recognize Pythagorean Triples when we see them.
Otherwise we'd have to work the calculator:
√(9² + 40²) = √1681 = 41
