We are given that we have $25 to pay for 6 fishing lures.
We can make an equality for this as follows:
Suppose price of one fishing lure is x dollars.
So we will use unitary method to find price of 6 fishing lures.
Price of 6 fishing lures = 6 * ( price of one fishing lure) = 6* x = 6x
Now we only have 25 dollars with us, so the price of 6 fishing lures has to be less than or equal to 25 dollars.
So creating an inequality,

Now in order to find price for one fishing lure, we have to solve this for x.
Dividing both sides by 6 we have,

Converting to decimal,

Answer : The price of one fishing lure must be less than or equal to $4.167
Let C be the amount of compost
T be the amount of topsoil
Each compost cost = $25
Cost of C compost = 25C
Each topsoil cost = $15
Cost of T topsoil = 15T
Amount of compost + amount of topsoil = 10
C + T = 10 -------> Equation 1
cost of C compost + cost of T topsoil = 180
25C + 15T = 180 --------> equation 2
Solve the first equation for C
C + T = 10
C = 10 - T
Now plug it in second equation
25C + 15T = 180
25 ( 10 - T) +15T = 180
250 - 25T + 15T = 180 (combine like terms)
250 - 10 T = 180 (Subtract 250 on both sides)
-10T = 180 - 250
-10T = -70 ( divide by -10 on both sides)
T = 7
She purchased 7 cubic yards of topsoil .
Answer:
1. 8.4 2. 15
Step-by-step explanation:
1. 4x+8y= 40
wen y= 0.8
4x+8×0.8=40
4x=40-8×0.8
4x= 40- 6.4= 33.6
....x= 33.6/4 = 8.4
2. 3a+b= 54
wen b= 9
3a+ 9= 54
3a= 54- 9
3a=45
.....a = 45/3 = 15
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Solution:
we are given with
Today the price of a Jeep is $25,000. In 1970, the price was $5,000.
So we can write
The price of a Jeep, today = $25,000
The price of a Jeep,in 1970 = $ 5,000
Relative Price means price of a good relative to other. Its a ratio of the two goods times 100.

Hence the price relative is $500/-
For this case we must find the product of the following expression:

We apply distributive property term to term:

We add similar terms:

Finally, the expression is as:

Answeer:
