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Readme [11.4K]
2 years ago
11

In today’s fast-paced, often "agile" software development, how can the secure design be implemented?

Computers and Technology
1 answer:
alexdok [17]2 years ago
7 0

Answer:

Answered below

Explanation:

The agile approach to software development involves development through the collaborative efforts of integrated and organised teams and users. Nowadays, people follow this approach because it allows for faster deployment, continuous updates as well as flexibility in development.

In the face of this rapid development and deployment, security design can be a challenge to keep up with.

Some steps to implement security in an agile environment include;

- Approaching security implementation in the same agile way as software development.

- Making software developers responsible for secure development and implementation.

- Utilising continuous integration of security practices by integrating security solutions with the development tools.

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1A network administrator notices that some newly installed Ethernet cabling is carrying corrupt and distorted data signals. The
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Answer:

EMI (Electromagnetic Interference).

RFI (Radio Frequency Interference).

Explanation:

The new ethernet cable is installed near the ceiling and it is close to fluorescent lights and electrical equipment.Since the ethernet cable is carrying corrupt and distorted data so it needs protection.The protection  should be from EMI(Electromagnetic Interference) and RFI(Radio Frequency Interference).

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2 years ago
A search box does all of the following EXCEPT ________.
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The answer is the first one
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1. What is the global marketplace?
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I know the answer for 1 is A

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Modify the sentence-generator program of Case Study so that it inputs its vocabulary from a set of text files at startup. The fi
Snezhnost [94]

Answer:

Go to explaination for the program code.

Explanation:

Before running the program you need to have these files created like below in your unix box.

Unix Terminal> cat nouns.txt

BOY

GIRL

BAT

BALL

Unix Terminal> cat articles.txt

A

THE

Unix Terminal> cat verbs.txt

HIT

SAW

LIKED

Unix Terminal> cat prepositions.txt

WITH

BY

Unix Terminal>

Code:

#!/usr/local/bin/python3

import random

def getWords(filename):

fp = open(filename)

temp_list = list()

for each_line in fp:

each_line = each_line.strip()

temp_list.append(each_line)

words = tuple(temp_list)

fp.close()

return words

articles = getWords('articles.txt')

nouns = getWords('nouns.txt')

verbs = getWords('verbs.txt')

prepositions = getWords('prepositions.txt')

def sentence():

return nounPhrase() + " " + verbPhrase()

def nounPhrase():

return random.choice(articles) + " " + random.choice(nouns)

def verbPhrase():

return random.choice(verbs) + " " + nounPhrase() + " " + prepositionalPhrase()

def prepositionalPhrase():

return random.choice(prepositions) + " " + nounPhrase()

def main():

number = int(input('Enter number of sentences: '))

for count in range(number):

print(sentence())

if __name__=='__main__':

main()

kindly check attachment for code output and onscreen code.

6 0
2 years ago
In this exercise you will debug the code which has been provided in the starter file. The code is intended to take two strings,
vampirchik [111]

Answer:

Here is the corrected program:

import java.util.Scanner; //to accept input from user

public class 02_14_Activity_one { //class name

    public static void main(String[] args) { //start of main method

    Scanner scan = new Scanner(System.in); //creates Scanner class object

  System.out.println("Enter first string"); //prompts user to enter first string

          String s1 = scan.nextLine(); //reads input string from user

  System.out.println("Enter second string"); //prompts user to enter second string

          String s2 = scan.nextLine(); //reads second input string from user

    System.out.println("Enter number of letters from each word"); //enter n

          int n = scan.nextInt(); //reads value of integer n from user

          System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

         } } //uses substring method to print a string made up of the first n letters of s1 and the last n letters of s2.

Explanation:

The errors were:

1.

Scanner scan = Scanner(System.in);

Here new keyword is missing to create object scan of Scanner class.

Corrected statement:

 Scanner scan = new Scanner(System.in);

2.

String s1 = nextLine();  

Here object scan is missing to call nextLine() method of class Scanner

Corrected statement:

String s1 = scan.nextLine();

3.

String s2 = Scanner.nextLine();

Here class is used instead of its object scan to access the method nextLine

Corrected statement:

String s2 = scan.nextLine();

4.

String n = scan.nextLine();

Here n is of type String but n is a whole number so it should be of type int. Also the method nextInt will be used to scan and accept an integer value

Corrected statement:

int n = scan.nextInt();

5.

System.out.println(s1.substring(1,n-1) + s2.substring(s1.length()-n));

This statement is also not correct

Corrected statement:

System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

This works as follows:

s1.substring(0,n) uses substring method to return a new string that is a substring of this s1. The substring begins at the 0th index of s1 and extends to the character at index n.

s2.substring(s2.length() - n ) uses substring method to return a new string that is a substring of this s2. The substring then uses length() method to get the length of s2 and subtracts integer n from it and thus returns the last n characters of s2.

The screenshot of program along with its output is attached.

7 0
2 years ago
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