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Rasek [7]
2 years ago
12

Here is a sample distribution of hourly earnings in Paul's Cookie Factory: Hourly Earning $6 up to $9 $9 up to $12 $12 up to $15

Frequency 16 42 10 The limits of the class with the smallest frequency are: ______.
Mathematics
1 answer:
labwork [276]2 years ago
5 0

Answer:

$12 up to $15

Step-by-step explanation:

Given

Hourly Earning: $6 - $9 || $9 - $12 || $12 - $15

Frequency:          16        ||         4      ||   10

Required

Determine the limits of the least frequency;

First, we have to determine the lowest frequency;

From the table. the lowest frequency is:

Lowest  = 10

Next is to determine the corresponding class limits

The corresponding class limit is $12 up to $15

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PLEASE HELP!
Bond [772]

Let x be the number of Standard Specials sold last Monday and y be the number of Deluxe specials sold last Monday.  

The Standard special sells for $2, then x Standard Specials cost $2x.

The Deluxe special sells for $4.50, then y  Deluxe specials cost $4.50y.

1. Last Monday, PB&P sold at least $200 worth of Standard and Deluxe peanut butter and pickle sandwich specials. This means that

2x+4.50y≥200.

2.  When all related business expenses are included, the Standard special costs $0.50 to prepare, then x Standard Specials cost $0.50x.

When all related business expenses are included, the Deluxe special costs $1.25 to prepare, then y Deluxe specials cost $1.25y.

Expenses were no more than $100, then

0.50x+1.25y≤100.

3. At least 30 Standard special were sold, then x≥30.

4. Graph all these inequalities (see attached diagram). As you can see only point (60,70) doesn't belong to needed region.

Answer: all points except point (60,70)

8 0
2 years ago
Read 2 more answers
A coordinate plane with a point plotted at and labeled (0, 2).
vaieri [72.5K]

Answer:

A,D, AND E

Step-by-step explanation:

4 0
2 years ago
Sixteen students each measured the weight of 25 pennies, in grams. The list shows their measurements. 60, 62, 65, 59, 63, 63, 63
saveliy_v [14]
Third one is the answer
5 0
2 years ago
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Given: EL- tangent, EK- secant <br> Prove: EJ·LK = EL·LJ
drek231 [11]

Answer:

This is possible.

Step-by-step explanation:

We can say that m<E=m<E, because of the Reflexive Property

Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.

With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).

Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), \frac{LK}{LJ} =\frac{EL}{EJ}.

With this ratio, we can cross multiply to get the desired result

EJ·LK=EL·LJ

Hope this helps with your RSM problem

Yup, i caught ya.

3 0
2 years ago
Beth wants to earn $500 to purchase a new phone. She earns $11 an hour at her job. The function B(h)=11h represents the amount o
My name is Ann [436]

Answer:

it well take her a month to buy so it will be bh11

3 0
2 years ago
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