Answer:
-26
Explanation:
The given binary number is 1110 0101. Also given that the signed binary number is represented using one's compliment.
We begin by computing the 1s complement representation of 1110 0101 by inverting the bits: 00011010
Converting 00011010 to decimal, it corresponds to 26.
So the 1s complement of the original number is 26. This means that the original number was -26.
<u><em>i just to the test on Plato and it said that A. accessibility is wrong the correct answer is d security #homeschoolrocks</em></u>
The answer is user EXEC mode. This is for setting, viewing, and testing system processes. In common, the user EXEC commands let you to link to remote devices, modify terminal line settings on a temporary basis, perform basic tests, and list system information. This also used by common system administrators, while the privileged EXEC mode is used by the root administrator. Use the enable and disable instructions to shift between the two levels. Access to the user-level EXEC command line needs a valid password.
Answer:
The correct option is;
Since information is based on data and data is just the facts, the knowledge gained from the information is always correct
Explanation:
In the of epistemological discipline that focuses on partial knowledge, a domain of information cannot be exhaustively understood, therefore, knowledge is said to be always partial or incomplete. Information can therefore be misleading as it can be made from a premise that is false even where the bearer of the information truly believes in the source of the data as being justified reason for the information, the bearer may not actually know the cause of the information. Knowledge gotten from information is therefore not always correct.
Answer:
Check the explanation
Explanation:
Algorithm for solving flood condition:
We suggest an algorithm to resolve the flood condition by creating a flow network graph.
Let us assume for every patient "p" there is a node "2" and for every hospital "h" there is a node "uh" and there is an edge ()T, uh) exist between patient "p" and hospital "h" with flow capacity of 1 iff patient "p" is reachable to hospital "h" within a half-hour.
Then source node "s" is made between all the patient-nodes by an edge with flow capacity of 1 and then the sink "t" is made by linking all the hospital nodes by an edge with capacity "[n/k]".
There is an approach to send patients to hospitals: when there is a source "s" to sink "t" flow of "n". We can send 1 flow-unit from source "s" to sink "t" along the paths (s, yp, uh, t) whenever a probable approach is available to send patients.
This approach of sending patients to hospitals doesn't break the capacity limitation of edges. Hence we can send patient "p" to hospital "h" with 1 flow- unit if edge(m uh) permits at least 1 flow- unit.
The running-time of this algorithm is found by finding the time needed to solve max-flow graph with nodes O(n+k) and edges O(
) edges.
