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Vadim26 [7]
2 years ago
5

Which of the following methodologies might be most appropriate if you have a system project with: unclear requirements; very fam

iliar technologies; not all that complex; reasonably reliable; a short time schedule and the schedule visibility?
a. Waterfall
b. Parallel
c. Iterative
d. System prototyping
e. Throwaway prototyping
Business
1 answer:
Anna71 [15]2 years ago
5 0

Answer:

The last option is wrong, the correct option to that question is: Extreme Programming.

And the correct answer is that option.

Explanation:

To begin with, the name of <em>"Extreme Programming"</em> refers to a specific methodology of development of software that mainly focuses in the improvement of software quality and the responsiveness to changing customers requirements. Moreover, this methodology best fits in the cases where the system project comes with unclear requirements and where there is a short time schedule due to the fact that as a type of agile software development it advocates frequent releases in short time cycles that are primarily focus on introducing checkpoints in where the requirements of the consumers who are unclear can be adopted.

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Elmo Johnson was late on his property tax payment to the county. He owed $7,500 and paid the tax four months late. The county ch
GrogVix [38]

Answer: $250

Explanation:

From the question, we are told that Elmo Johnson was late on his property tax payment to the county and that he owed $7,500 and paid the tax four months late.

We are further told that the county charges an annual penalty of 10%. The amount of the penalty for the four-month period goes thus:

Annual penalty = 10% × $7500

= 0.1 × $7500

= $750

Since he is four months late and there are twelve months in a year, this will be:

= $750 × 4/12

= $750 × 1/3

= $750/3

= $250

8 0
2 years ago
5. Which of the following is true for the party paying fixed in an interest rate swap? Assume no other transactions with the cou
Eva8 [605]

Answer:

The answer is option A, There is more credit risk when the yield curve is upward sloping than when it is downward sloping

Explanation:

Solution

In an interest swap rate, when we receive floating, and pay fixed, in upward sloping yield curve, we are going to receive increase of  cash flows and therefore going to pay fixed and so, the counterpart will be at  a loss in slopping upward yield curve, and hence, we will have a credit risk that will be greater.

6 0
2 years ago
Firm X has declared a stock dividend that pays one share of stock for every five shares owned. After the stock dividend, earning
attashe74 [19]

Answer:

Option (b) Decline 20%

Explanation:

Data provided in the question:

Firm X has declared a stock dividend that pays one share of stock for every five shares owned

Therefore,

The increase in number of shares

= [ 1 ÷ 5 ] × 100%

= 20%

Thus,

The earnings per share will decrease by the amount of increase in number of shares i.e decrease by 20%

Hence,

Option (b) Decline 20%

8 0
2 years ago
You just purchased a three-month BP call option (exercise price $75) and a three-month BP put option (exercise price $75). The c
enyata [817]

Answer:

Correct option is C.

<u>Maximum potential loss from this position is $800</u>

Explanation:

Premium paid for call option = $6 * 100 = $600

Premium paid for put option = $2 * 100 = $200

Total cost = $600 + $200 = $800

In case the price of underlying stock falls below $75, call option will be exercised. If the price rises above $75 cal option would be, exercised. In case price stays at $75, nothing would be done. In any case the amount lost cannot exceed the cost of $800 that has been paid for the options.

3 0
2 years ago
Holman company owns equipment with an original cost of $95,000 and an estimated salvage value of $5,000 that is being depreciate
brilliants [131]
Depreciation is a way not only to recognize the lost value over time of an asset, but also a way to recognize the expense of the asset over time. To this end, we want to see the value of the asset get smaller, and a piece of the asset on the the income statement ever period. 
The depreciation base is 95,000 -5,000 = 90,000, and the depreciation period is 90,000/15,000 = 6 years.
The journal entry every year will be 
Dec. 31
Debit: Depreciation expense 15,0000
Credit: Accumulated Depreciation       (15,000)
Accumulated depreciation is a *contra-asset* account on the balance sheet that reduces the value of the the depreciable asset. 
7 0
2 years ago
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