<h2>
Answer with explanation:</h2>
Given : An urn contains 2 red marbles and 3 blue marbles.
Total marbles = 2+3=5
a) The general ways in which the person could get a red marble and a blue marble are :
1) He draws red marble first and then second marble as blue.
2) He draws blue marble first marble and then second marble as red.
b) The number of ways to get one red and one blue marble is given by :-
(i)
c) Number of ways to get 2 marbles from 5 is given by :-
(ii)
Now, The probability the person gets a red and a blue marble will be :-
[Divide (i) by (ii)]
Hence, the probability the person gets a red and a blue marble= 0.6
Answer:
Step-by-step explanation:
We assume that there are 100 sour candies, Thus-
26 % of candy are grape implies that 26% of 100 candies are grape that is equal to 26
Now remaing candies that are not grape are 100-26 = 74
Based on the rule of multiplication:
P(A ∩ B) = P(A)/ P(B|A)
In the beginning, there are 26grape candies, probability of choosing first grape candy = 26C1 = 26
After the first selection, we replace the selected grape candy so there are still 100 candies in the bag P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!
= 50 x 33 x 98
So probability =1/ 50 x 33 x 98 x 26
= 1/4204200
1.5r+15=2.25r
Combine like terms: 1.5r+15-1.5r=2.25r-1.5r
15=0.75r
Get the unknown alone: 15/.75=.75/.75r
20=r or r=20 :)
c(x)=9x+89
I know that you don't have the answer listed, but it is the correct answer.
Answer:
Step-by-step explanation:
we know that
In the triangle XYZ
Applying the law of sines
solve for z
