X - Ernie, y - Kaylin, z - Tria
x = y + 121.50
z = 3y - 35
x + y + z = 579
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z = 3 y - 35 => - 3 y + z = -35
y + 121.50 + y + z = 579
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- 3 y + z = - 35 / · ( -1 )
2 y + z = 457.50 (we will use the elimination method)
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3 y - z = 35
2 y + z = 457.50
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5 y = 492.5, y = 492.5 : 5 = 98.5
z = 3 · 98.5 - 35
z = 260.5
Tria earned $260.5
5 + 0.50p = 6.50
0.50p = 6.50 - 5
0.50p = 1.50
p = 1.50/0.50
p = 3 <=== the vehicle had 3 people in the vehicle
8 = 2*2*2
9=3*3
We are finding the least common multiple
LCM = 2*2*2*3*3
LCM = 72
Sam and Carlos have each knocked down 72 pins
Answer:
see below
Step-by-step explanation:
1.5x + 5y = 1152
x = 4y – 2
We can substitute the second equation into the first equation
Which one-variable linear equation can be formed using the substitution method?
1.5(4y-2) +5y = 1152
Distribute
6y -3 +5y = 1152
Combine like terms
11y-3 = 1152
Add 3 to each side
11y-3+3 = 1152+3
11y = 1155
Divide each side by 11
11y/11 = 1155/11
y = 105
How many $5 raffle tickets were sold?
105 5 dollar tickets were sold
Now we need to find the number of 1.50 tickets
Which equation can be used to determine how many $1.50 raffle tickets were sold?
x = 4y – 2
x = 4(105) -2
=420-2
= 418
How many $1.50 raffle tickets were sold?
418 $1.50 tickets were sold
Did you get an answer? I thought it was lump sum, but i don't know which option
