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trasher [3.6K]
2 years ago
12

L= a+(n-1)d SOLVE FOR N ​

Mathematics
1 answer:
Deffense [45]2 years ago
8 0

Answer:

n = \frac{l-a}{d}+1

Step-by-step explanation:

l= a+(n-1)d\\

l -a =(n+1)d

Divide both sides of the equation by d

\frac{l-a}{d} = \frac{(n-1)}{d}\\ \\\frac{l-a}{d} = n-1\\\\\frac{l-a}{d}+1 = n

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The equation |x − 8| = 3 represents the minimum and maximum percent of people in a survey who are undecided about an issue. What
icang [17]
| x - 8| = 3

x - 8 = 3            - (x - 8) = 3
x = 3 + 8           -x + 8 = 3
x = 11                -x = 3 - 8
                         -x = - 5
                           x = 5

Minimum : 5%    Maximum : 11%    if u need them added it is 16%
5 0
2 years ago
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If 49x2 + 28x - 10 is rewritten as p2 + 4p -10, what is p in terms of<br> p=
madam [21]

Answer:

p=7x

Step-by-step explanation:

49x^[2] + 28x - 10 = p^[2] + 4p -10

This equation is in the form a^[2]x + bx + c.

<u><em>The 'c' is common for both equations, this means the 'a' and 'b' must also be common. </em></u>

There are two ways to find p: 'a' or 'b'

<u>a method</u>

49x^[2] = p^[2]

=> The square root of both sides = 7x = p

<u>b method</u>

28x = 4p

28x/4 = 4p/4

7x = p

6 0
2 years ago
The range for the Kentucky temperature is ____
natka813 [3]

Answer:

1) 6.1

2)5.1

3)2.8

4)2.4

5)I don't know what the last one is asking for, are there answer choices

Step-by-step explanation:

1)Max-min=58.3-52.2=6.1

2)Max-min=55-48.9=5.1

3)Upper quartile- lower quartile= 57.3-54.5=2.8

4)Upper quartile- lower quartile= 53.3-50.9=2.4

5) I don't know what this one is asking

6 0
2 years ago
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The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3
viva [34]

Answer:

119.45 m

Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

\triangle ABC represents the 1st angle of elevation of sun i.e.  58°

\triangle ABD represents the 2nd angle of elevation of sun i.e.  36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = h m

Let side BC = x m

Now, let us apply tangent rules in \triangle ABC, \triangle ABD one by one:

tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)

tan36^\circ = \dfrac{h}{x+90}

Putting value of x using equation (1):

tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}

119.45 m is the height of pole.

7 0
2 years ago
PLEASE HELP I HAVE NO IDEA
Agata [3.3K]
Part 1:

The table showing the decreasing debt is shown as follows:

\begin{tabular}&#10;{|c|c|c|c|}&#10;Starting Balance&Interest Accrued&Payment&Closing Balance\\[1ex]&#10;\$1,853.42&\$22.39&\$400&\$1,475.81\\\$1,475.81&\$17.83&\$400&\$1,093.64\\\$1,093.64&\$13.21&\$200&\$906.85\\\$906.85&\$10.96&\$200&\$717.81\\\$717.81&\$8.67&\$200&\$526.48\\\$526.48&\$6.36&\$200&\$332.84\\\$332.84&\$4.02&\$200&\$136.86\\\$136.86&\$1.65&\$138.51&-&#10;\end{tabular}

The column for interest accrued is obtained by the folmular

I=P(1+0.155)^{\frac{1}{12}}

where P is the month's starting balance.



Part 2:

From the table, the last payment is $138.51



Part 3:

The total amount paid by the time the credit card is payed of is the summation of the "payment" column of the table.

Thus, the total amount is given by:

Payment\ total=2(400)+5(200)+138.51=\$1,938.51



Part 4:

The debt ratio is given by

Debt\ ratio= \frac{debt}{limit} = \frac{1,853.42}{3,000} \approx0.62
4 0
1 year ago
Read 2 more answers
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