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Art [367]
2 years ago
3

O produtor rural Ricardo Antunes Peixoto, 55 anos, teve uma surpresa enquanto perfurava um poço artesiano em sua fazenda, na zon

a rural de Brasília de Minas (MG). "Não saiu água, mas saiu fogo", diz, espantado. Uma equipe com cinco operários de uma empresa especializada trabalhou durante dois dias na propriedade para abrir o poço de água, mas, após escavarem 204 metros, o que encontraram foi um produto inflamável, que seria gás natural. O dono da fazenda Lagoa Misteriosa espera lucrar com a descoberta da reserva de gás. "Pelo menos, que se têm notícias no estado, este é o primeiro caso. Agora, com o dinheiro que eu vender o gás, vou abrir [um novo poço] para ter a minha água". Disponível em: . Acesso em: 12 abr. 2013. Considerando a combustão completa do metano, nas CNTP, determine a energia liberada na queima de 224 L de metano que foi em encontrado no poço desse agricultor. Dados: C–H = 416 kJ/mol C?O = 805 kJ/mol O?O = 498 kJ/mol O–H = 464 kJ/mol A. –2 660 kJ/mol B. –8 060 kJ/mol C. –1 220 kJ/mol D. –4 030 kJ/mol E. –2 600 kJ/mol
Mathematics
1 answer:
love history [14]2 years ago
7 0

O produtor rural Ricardo Antunes Peixoto, 55 anos, teve uma surpresa enquanto perfurava um poço artesiano em sua fazenda, na zona rural de Brasília de Minas (MG). "Não saiu água, mas saiu fogo", diz, espantado. Uma equipe com cinco operários de uma empresa especializada trabalhou durante dois dias na propriedade para abrir o poço de água, mas, após escavarem 204 metros, o que encontraram foi um produto inflamável, que seria gás natural. O dono da fazenda Lagoa Misteriosa espera lucrar com a descoberta da reserva de gás. "Pelo menos, que se têm notícias no estado, este é o primeiro caso. Agora, com o dinheiro que eu vender o gás, vou abrir [um novo poço] para ter a minha água". Disponível em: . Acesso em: 12 abr. 2013. Considerando a combustão completa do metano, nas CNTP, determine a energia liberada na queima de 224 L de metano que foi em encontrado no poço desse agricultor. Dados: C–H = 416 kJ/mol C?O = 805 kJ/mol O?O = 498 kJ/mol O–H = 464 kJ/mol A. –2 660 kJ/mol B. –8 060 kJ/mol C. –1 220 kJ/mol D. –4 030 kJ/mol E. –2 600 kJ/mol

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Assuming that am supposed to calculate the the mean absolute deviation of 
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