How do you divide 506 in the ratio 2:4:5 ?
1 answer:
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Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
You did not attach any picture to solve this problem. We cannot calculate for the value of A’ and D’ without the correct graph. However, I think I found the correct graph (see attached), please attach it next time.
So we are given that the figure is dilated by a factor of, meaning that all of its end points are multiplied by 2. By this rule, all we have to do is to simply multiply the initial coordinates of A and D by 2 to get A’ and D’, that is:
A’ = (-1 * 2, -1 * 2) = (-2, -2)
<span>D’ = (2 * 2, -1 * 2) = (4, -2)</span>
