Find the value of y if EF = EG.
1 answer:
Answer:
<h2>55°</h2>Step-by-step explanation:
The question lacks appropriate diagram. Find the diagram in the attachment.
From the diagram, it can be seen that the triangle is an isosceles triangle because two of its sides are parallel (i.e the same). Since two of the sides are the same, hence the two base angles will be the same.
From the diagram, <EFG = <EGF
Since <EFG = 55° hence <EGF = y = 55°
<em>Hence the va;ue of y is 55°</em>
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Answer:
Step-by-step explanation:
We have the following expression:
We can find the GCF with the following steps.
1. Find the GCF for the numerical part 15 and -21
The factors for 15 are : 1,3,5,15
The factors for -21 are -21,-7,-3,-1,1,3,7,21
And the common factors are 1,3
The GCF for the numerical part is 3*1 = 3
2. Find the GCF for the variable
The factors of x^2 are : x*x
The factors of x are: x
The common factors are x for this case, so then the GCF for the variable part is x
3. Multiply the two results from steps 1 and 2
GCf= 3*x = 3x
If we consider the new expression:
We can find the GCF with the following steps.
1. Find the GCF for the numerical part 15 and -21
The factors for 15 are : 1,3,5,15
The factors for -21 are 1,3,7,21
And the common factors are 1,3
The GCF for the numerical part is 3*1 = 3
2. Find the GCF for the variable
The factors of x^2 are : x*x
The factors of x are: x
The common factors are x for this case, so then the GCF for the variable part is x
3. Multiply the two results from steps 1 and 2
GCf= 3*x = 3x
And as we can see both GCF are equal. So then we satisfy the condition required.
So, on day 1, the plant was say "P" cm tall.
then 2 weeks go by, or 14 days, and the plant grew to 452 cm.
then 2 weeks go by, or 14 days, and the plant grew to 452 cm.