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2 years ago

7. A BOOKSTORE WAS SELLING BOOKS FOR 50% OFF. A SHELF IN THE STORE HAD A SIGN AS SHOWN:

Mathematics

1 answer:

olga55 [171]2 years ago

4 0

Answer:

Leta payed $37.50

Step-by-step explanation:

50% is another way of saying half. So half of 100 is 50. She is down to $50.00 If you take another 25% off then it is $37.50. This is because 25% of 50 is 12.50. If you subtract 12.5 from 50 then you get 37.50. This is how I know it is $37.50. Hope this helps! :)

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The drama club members at Millie’s middle school are selling tickets to the school play. Millie wants to determine the average n

White raven [17]

The first sampling method is Convenient Sampling. It is biased sampling and it is not representative of a random sample.

The second sampling method is Systematic Sampling. If this method of sampling is drawn from the population, it is an efficiently randomized sampling method.

Let us review the given answers.

1. Both samples should be exactly the same.
INCORRECT

2. Neither sample will be representative.
Because the second sampling method can be random, this answer is
INCORRECT.

3. The first sampling method, ..., is the most representative,
INCORRECT

4. The second sampling method, ..., is the most representative.
CORRECT

3 0

2 years ago

Read 2 more answers

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago

Nicole bought six pounds of apples at $1.50 per pound. The store had a discount of $2 off her total purchase. Nicole and her fri

Andru [333]

Answer:

Step-by-step explanation:

Total amount of apples that Nicole bought was 6 pounds.

Each pound of apple cost $1.50

This means that the total cost of the 6 pounds of apple that Nicole bought would be

6 × 1.5 = $9

The store had a discount of $2 off her total purchase. This means that the amount that was paid is

9 - 2 = $7

If Nicole and her friend then divided the cost of the purchase evenly, let x represent the amount that each of them would pay. Therefore, the expression that can be used to determine how much Nicole and her friend each paid for the apples would be

x = 7/2

6 0

2 years ago

Mrs. Harrison has a jar full of cookies.

Elanso [62]

Answer:

Step-by-step explanation:

12 oatmeal cookies divided by 3 sugar cookies is 4. AKA there are 4 groups of 3.

4 0

2 years ago

Read 2 more answers

Fred wants to find 48+34 using compensation.He says you can take 2 from 34 and give it to 48 to make 50.What is the sum?Explain

Montano1993 [528]

It is easier to add 50 to a number than 48 because 50 has a zero in it which makes an addition simpler.

48 + 34 = borrow 2 from 34 and add to 48

= 50 + 32 50 + 32 is 82

= 82

6 0

2 years ago