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2 years ago

A bag of potato chips costs $6.99 and comes with 87 chips. If you could buy them

Mathematics

2 answers:

mel-nik [20]2 years ago

4 0

So basically the answer is 26

blondinia [14]2 years ago

3 0

Answer:

125

Step-by-step explanation:

By doing 6.99/87, we can figure out that each chip costs approximately 8 cents. With this in mind, we can divide 10 by 0.08 to get 125.

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You play darts with a friend. The board is a circle with a 6-inch radius. The “Bull’s Eye” is a smaller circle in the center of

Kryger [21]

The area of the board = πr² = 36 π square inches
Area of the Bull's eyes = πr² = 0.0625 π square inches

If a dart is thrown at random, the probability that it will hit the bull's eye can be calculated as:

Area of Bulls's Eyes divided by Area of Complete Board

So, probability of hitting the bulls'e eye = 1/576 = 0.001736

The friend hit Bull's eye once in a 500 throws. So the probability of hitting the Bull's eyes will be = 1/500 = 0.002

If we compare the two probabilities, they are close to each other. So we can conclude that the friend is not a skilled player and she hit the bull's eye just by chance.

5 0

2 years ago

The map shows the location of a mall, library, and school in a city:

Kamila [148]

Answer:

A) 8 miles.

Step-by-step explanation:

We haven been given a map that shows the location of a mall, library, and school in a city.

First of all we will find the distance traveled by Britney from school to mall and mall to library using distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting the coordinates of school and mall in distance formula we will get,

$\text{Distance between school and mall}=\sqrt{(10-10)^2+(-4-6)^2}$

$\text{Distance between school and mall}=\sqrt{(0)^2+(-10)^2}$

$\text{Distance between school and mall}=\sqrt{0+100}$

$\text{Distance between school and mall}=10$

Now let us find distance between mall and library.

$\text{Distance between mall and library}=\sqrt{(10--14)^2+(6-6)^2}$

$\text{Distance between mall and library}=\sqrt{(10+14)^2+(0)^2}$

$\text{Distance between mall and library}=\sqrt{(24)^2+(0)^2}$

$\text{Distance between mall and library}=\sqrt{576+0}$

$\text{Distance between mall and library}=24$

$\text{Total distance covered by Britney}=\text{10 miles +24 miles}$

$\text{Total distance covered by Britney}=\text{34 miles}$

Therefore, Britney traveled 34 miles.

Now let us find the distance covered by Alice by substituting coordinates of school and library in distance formula.

$\text{Distance covered by Alice}=\sqrt{(10--14)^2+(-4-6)^2}$

$\text{Distance covered by Alice}=\sqrt{(10+14)^2+(-10)^2}$

$\text{Distance covered by Alice}=\sqrt{(24)^2+(-10)^2}$

$\text{Distance covered by Alice}=\sqrt{576+100}$

$\text{Distance covered by Alice}=\sqrt{676}$

$\text{Distance covered by Alice}=26$

Therefore, Alice traveled 26 miles.

$\text{The number of miles Britney traveled more than Alice}=\text{34 miles -26 miles}$

$\text{The number of miles Britney traveled more than Alice}=\text{8 miles}$

Therefore, Britney traveled 8 miles more than Alice and option A is the correct choice.

4 0

2 years ago

Read 2 more answers

Which numbers are rational? I. 2.2222222... II. 2.20220222... III.2.345

Sedbober [7]

Answer:

2.345

Step-by-step explanation:

8 0

2 years ago

a group of 42 children all play tennis or football or both sports, the same number play tennis as play just football, twice as m

lara31 [8.8K]

Answer: Football = 35 children

Step-by-step explanation:

I created a Venn diagram and labeled it as follows:

Tennis only = x

Both Tennis & Football = y

Football only = x + y

Total children = x + y + x + y

42 = 2x + 2y

We are also given that y = 2x (twice as many play both tennis & football as just play tennis)

Now we have two equations and can use substitution to solve for x & y:

42 = 2x + 2y

y = 2x

42 = (y) + 2y

42 = 3y

14 = y

Now let's find x:

y = 2x

14 = 2x

7 = x

We are asked to find how many children play football.

Football = x + y

Both Tennis & Football = y

Total Football = x + 2y

= 7 + 2(14)

= 7 + 28

= 35

5 0

2 years ago

How many words can be formed by using the W,X,Y,Z if repetitions is not allowed?

Setler [38]

Answer:

Step-by-step explanation:

What you have here is a permutation, seeing as each element can only be used once.

We have 4 letters initially, so we can choose any 1 as our first letter. We have 4 choices for our first letter

However, once we choose our first letter, we can't use it anymore, so, for our second letter, we can only choose from the remaining 3 letters.

Furthermore, once we choose our second letter, we can only choose our 3rd letter from the remaining two letters we didn't choose yet.

Finally, our last letter will always be the one we didn't choose the last 3 times. So there is only one choice here.

Going off of this, we have four choices for the 1st letter, three choices for the 2nd letter, two choices for the 3rd letter, and one choice for the 4th letter

The way to calculate how many permutations we have without repetition is using factorials

Where N is the number of elements you have.

In this case, it would be 4!

4! is 4 * 3 * 2 * 1

Which equals 24

If you notice, each number in 4! is the number of options we have for each choice. 4, then 3, and so on

5 0

2 years ago