A 50.00-g sample of metal at 78.0°C is dropped into cold water. If the metal sample cools to 17.0°C and the specific heat of met
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The new volume at standard pressure of 1 atm is 21294 liters.
Explanation:
Data given:
Initial volume of the gas V1 = 338 liters
initial pressure on the gas P1 = 63 atm
standard pressure as P2 = 1 atm
Final volume at standard pressure V2 =?
The data given shows that Boyle's law equation is to used:
P1V1 = P2V2
rearranging the equation to calculate V2,
V2 =
Putting the values in the equation:
V2 =
= 21294 L
as the pressure on the gas is reduced to 1 atm the volume of the gas increased incredibly to 21294 litres.
Answer:
The empirical formula is =
The formula of Valproic acid =
Explanation:
Mass of water obtained = 0.166 g
Molar mass of water = 18 g/mol
Moles of = 0.166 g /18 g/mol = 0.00922 moles
2 moles of hydrogen atoms are present in 1 mole of water. So,
<u>Moles of H = 2 x 0.00922 = 0.01844 moles </u>
Molar mass of H atom = 1.008 g/mol
<u>Mass of H in molecule = 0.01844 x 1.008 = 0.018588 g </u>
Mass of carbon dioxide obtained = 0.403 g
Molar mass of carbon dioxide = 44.01 g/mol
Moles of = 0.403 g /44.01 g/mol = 0.009157 moles
1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,
<u>Moles of C = 0.009157 moles </u>
Molar mass of C atom = 12.0107 g/mol
<u>Mass of C in molecule = 0.009157 x 12.0107 = 0.11 g </u>
<u>Given that the Valproic acid only contains hydrogen, oxygen and carbon. </u>So,
Mass of O in the sample = Total mass - Mass of C - Mass of H
Mass of the sample = 0.165 g
<u>Mass of O in sample = 0.165 - 0.11 - 0.018588 = 0.036412 g </u>
Molar mass of O = 15.999 g/mol
<u>Moles of O = 0.036412 / 15.999 = 0.002276 moles</u>
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<u>Taking the simplest ratio for H, O and C as: </u>
<u>0.01844 : 0.002276 : 0.009157</u>
<u> = 8 : 1 : 4</u>
The empirical formula is =
Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.
Thus,
Molecular mass = n × Empirical mass
Where, n is any positive number from 1, 2, 3...
Mass from the Empirical formula = 4×12 + 8×1 + 16= 72 g/mol
Molar mass = 144 g/mol
So,
Molecular mass = n × Empirical mass
144 = n × 72
<u>⇒ n = 2</u>
The formula of Valproic acid =