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2 years ago

11

Millie needs to cook a roast lamb for 1 hour and 50 minutes at 356c. How much does the roast weigh in kilo grams if the recommen

dation is 20 minutes for every 250 grams

2 answers:

Andrew [12]2 years ago

6 1

Answer:

The roast weighed 1.375 kg

Step-by-step explanation:

Here, we want to know what the roast lamb will weigh in kilograms given its cooking time.

From the question, we are told that to cook 250 grams, 20 minutes is need.

So let’s make a relationship here,

Firstly let’s express 1 hour and 50 minuets in minutes, that will be 60 + 50 = 110 minutes( 1 hour is 60 minutes)

Now;

let’s have our relationship;

20 minutes = 250 grams

110 minutes = x grams

By cross multiplication;

20 * x = 250 * 110

20x = 27,500

x = 27500/20

x = 1,375 grams

But, mathematically 1000g = 1kg

So 1,375 will be 1375/1000 = 1.375 kg

Guest

1 year ago

Wrong

Guest

1 year ago

It’s write but it not as easy as mine

Guest1 year ago

0 0

250g per 20min 1h and 50min = cook time

60 + 50 = 110

110÷20=5.5

250 x 5.5 = 1375k

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Given RT below, if S lies on RT such that the

defon

Answer:

(-2, -3)

Step-by-step explanation:

If a segment having extreme ends as $(x_1,y_1)$ and $(x_2,y_2)$ is divided by a point (x, y) in the ratio of m:n,

x = $\frac{mx_2+nx_1}{m+n}$

y = $\frac{my_2+ny_1}{m+n}$

Since, a line RT has extreme ends as R(-5, 3) and T(-1, -5) then a point S(x, y) which divides RT in the ratio of 3 : 1 will be,

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2 years ago

arleen has a gift card for a local lawn and garden store. she uses the gift card to rent a roller for 4 days. it cost $17 per da

kaheart [24]

Answer:

We use negative values for the money Arleen spends.

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b) We determine the amount on money she has left on the gift card after renting the tiller and buying the rake:

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Step-by-step explanation:

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2 years ago

goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC = $\frac{b}{a-c}$

Step-by-step explanation:

According to midpoint formula

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the coordinate (x,y) of mid point of line PQ is given by

$x=\frac{x_{1} +x_{2} }{2}$ and $y=\frac{y_{1} +y_{2} }{2}$

now from the given diagram A is the mid point of line joining R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

$x=\frac{0+2a}{2}= a$ and $y=\frac{0+2b}{2} =b$

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

$x= \frac{2c+2c}{2} =2c$ and $y=\frac{2d+0}{2} =d$

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

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then the slope of PQ = $\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

hence slope of AD= $\frac{0-b }{c-a}$

= $\frac{-b}{c-a}$

= $\frac{-b}{-(a-c)}$

= $\frac{b}{a-c}$

and slope of BC = $\frac{d-(b+d)}{2c-(a+c)}$

= $\frac{d-b-d}{2c-a-c}$

= $\frac{-b}{c-a}$

= $\frac{b}{a-c}$

so we have

slope of AD and BC = $\frac{b}{a-c}$

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