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Darina [25.2K]
2 years ago
14

Morgan, Dakota and Taylor showed their work solving the equation 7x + 5x +1= 73. Identify the student with the invalid first ste

p and justify your reasoning. Morgan 7x + 5x + 1 = 73 12x + 1 = 73 Dakota 7x + 5x + 1 = 73 7x + 6x = 73 Taylor 7x + 5x + 1 = 73 7x + 5x = 72​
Mathematics
2 answers:
Fittoniya [83]2 years ago
8 0

Answer:

Taylor is incorrect.

Step-by-step explanation:

As you can see, Taylor failed to add 1 to her equation. This ruins the whole first step. She also used 72 instead of 73 for the answer. Taylor is incorrect.

Pavel [41]2 years ago
7 0

Answer:

Morgan, Dakota and Taylor showed their work solving the equation 7x + 5x +1= 73. Identify the student with the invalid first step and justify your reasoning. Morgan 7x + 5x + 1 = 73 12x + 1 = 73 Dakota 7x + 5x + 1 = 73 7x + 6x = 73 Taylor 7x + 5x + 1 = 73 7x + 5x = 72​

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

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10 students, so n = 10

We have to find:

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Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684

P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that p = 0.3758

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P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

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Step-by-step explanation:

Given

y = \frac{2}{5}x - 5

Required

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This is shown as follows;

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Open Bracket

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<em>Hence, the correct option is D</em>

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