The answer for x^2-6x-16 is (x-8) (x+2) or x = -2
The value of sin(30°) is: One-half ⇒ 2nd answer
Step-by-step explanation:
In a right triangle there are two acute angles, the side opposite to the right angle is called hypotenuse, and the other two sides are opposite and adjacent to the acute angles
- sine the acute angle (sin) = opposite side to it/hypotenuse
- cosine the acute angle (cos) = adjacent side to it/hypotenuse
- Tangent the acute angle (tan) = opposite side to it/adjacent side to it
In Δ QRS:
∵ m∠QRS = 90°
∵ SQ is opposite to ∠QRS
∴ SQ is the hypotenuse
∵ SQ = 10 units
∴ The hypotenuse = 10
∵ m∠RSQ = 30°
- The opposite side to ∠RSQ is RQ
∵ RQ = 5 units
∴ The opposite side to the angle of 30° = 5
∵ sin(30°) = opposite side to 30°/hypotenuse
∵ The opposite side to angle 30° = 5
∵ The hypotenuse = 10
∴ sin(30°) = 
∴ sin(30°) = 
The value of sin(30°) is: One-half
Learn more:
You can learn more about the trigonometry ratios in brainly.com/question/9880052
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Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes

.
The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.
The probability of selecting one coin is

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.
P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.
Thus

</span><span>P(B) means that the first envelope contains a quarter AND the
second envelope contains a quarter
</span><span>Thus

Therefore,

Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
</span><span>

</span><span>

</span><span>
Therefore,

</span>
I believe this would take the form of an exponential
equation:
A = Ao (1 + r)^t
where A is final population, Ao is initial population, r
is rate of growth and t is time
A / Ao = (1 + r)^t
log A / Ao = t log (1 + r)
t = (log A / Ao) / log (1 + r)
t = [log (1000 / 550)] / log (1.075)
t = 8.27 years
SO the answer is B) about 9 years