Answer:
D. Aa
Explanation:
Given:
Jill (mother) is heterozygous for gene A --------- i.e Jill = Aa
Jack (father) who is homozygous recessive for gene A-------- i.e Jack = aa
Now if both cross and fertilization occurs, we have:
A a
a Aa aa
a Aa aa
The offsprings are (Aa, Aa, aa, aa)
Nondsijunction is the inability of homologous chromosomes to seperate properly during cell division. Now, we were told that this fertilization undergone nondisjunction in meiosis 1. Hence, both homologous chromosome move into the same daughter cells instead of different daughter cells because separation of homologous chromosome does not occur properly.
Therefore the result of these fertilization of a normal haploid sperm with an egg that had undergone nondisjunction in meiosis yields offspring with genotype Aa of their Mother (Jill).
Answer:
p53 gene is an important gene that regulates the proper functioning of the cell. This gene plays an important role in the cell cycle progression and acts as genome guardian.
Any mutation in p53 leads to the formation of the different types of cancer cells. The p53 gene is activated by teh phosphorylation at the particular sites. High levels of phosphorylated p53 in the cell indicates that the cells DNA is highly damaged and mutated.
The protein would have the wrong shape.
Hope this helps!
