Answer:
The correct answer is c. water to move out of the strawberry, making it smaller
Explanation:
Osmosis is the process refers to the movement of liquid molecule from the area of high solute concentration to an area of low solute concentration through a semipermeable membrane to equalize the osmotic balance.
Osmosis is important for any cell to maintain a proper osmotic balance of the cell. So if sugar is sprinkled on a strawberry the solute concentration outside the strawberry cells will increase which will result in water release from the cell.
This release of water from the cell will shrink the strawberry and make it small. Therefore the correct answer is c.
answer mercury
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Answer:
Scenario I, Scenario II, and Scenario III are examples of competitive networks.
Explanation:
There are different examples of nets as interactions between species. Trophic net is a very common example of these interactions. Another one is the competitive network.
The competitive network refers to the competition for the same resource between different species in a community or ecosystem. When a resource is useful for two or more species, they compete to gain it.
The competitive network can be represented as arrows that indicate which is the dominant species over the other. This representation must be done with a<u> minimum of two species interacting</u> and indicating through the direction of the arrow, which species wins the competition.
There is a competitive hierarchy when there are more than two species, for example, species A, B, and C. Species A dominates over the other two, and species B dominates over species C. In these cases, the representation would be A --> B --> C. This reflects a transitive competitive network. Species A displaces species B and C, and species B displaces species C. The only species that can persist is A. This example can be extended to <u>any number of species</u>, which suggests that a hierarchy network does not promote biologic diversity.
Answer:
The genotype of parents for 6 exceptional cross was
Bb * bb
Result for crossing the black and white guinea pigs from the 6 exceptional cases.
Bb * bb
Bb, Bb, bb, bb
Explanation:
Here trait for black guinea is dominant over the trait for white guinea
There is a possibility that for remaining 6 crosses, the genotype of parents would be as follows
Black guinea pig - Bb
White guinea pig - bb
Now when these two genotypes are crossed the following offsprings are produced
Bb * bb
Bb, Bb, bb, bb
Thus, out of four offspring half of them are heterozygous black and remaining half of them are white in color.
Now if these black and white guinea pigs from the 6 exceptional cases with genotype Bb and bb are crossed respectively, then following offspring are produced
Bb * bb
Bb, Bb, bb, bb
Answer:
1. They make up part of a negative feedback system that promotes insect population growth.
Explanation:
If the Martin becomes extinct, it will cause an increase in insect population, as there is no predator to maintain the population. A population growth of insects would be a problem as it will destroy crops and agriculture.