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Setler [38]
2 years ago
5

Mahon Corporation has two production departments, Casting and Customizing. The company uses a job-order costing system and compu

tes a predetermined overhead rate in each production department. The Casting Department’s predetermined overhead rate is based on machine-hours and the Customizing Department’s predetermined overhead rate is based on direct labor-hours. At the beginning of the current year, the company had made the following estimates:
Casting Customizing
Machine-hours 20,600 16,600
Direct labor-hours 7,100 8,300
Total fixed manufacturing overhead cost $140,080 $83,000
Variable manufacturing overhead per machine-hour $2.40
Variable manufacturing overhead per direct labor-hour $4.80

During the current month the company started and finished Job T138. The following data were recorded for this job: Job T138: Casting Customizing Machine-hours 80 30 Direct labor-hours 9 60 The amount of overhead applied in the Customizing Department to Job T138 is closest to:_________
Business
1 answer:
seropon [69]2 years ago
8 0

Answer:

Allocated MOH= $888

Explanation:

Giving the following information:

The Customizing Department’s predetermined overhead rate is based on direct labor-hours.

Customizing

Direct labor-hours 8,300

Total fixed manufacturing overhead cost $83,000

Variable manufacturing overhead per direct labor-hour $4.80

Job T138:

Direct labor-hours 60

<u>First, we need to calculate the predetermined overhead rate:</u>

Predetermined manufacturing overhead rate= total estimated overhead costs for the period/ total amount of allocation base

Predetermined manufacturing overhead rate= (83,000/8,300) + 4.8

Predetermined manufacturing overhead rate= $14.8 per direct labor hour

<u>Now, we can allocate overhead to Job 138:</u>

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

Allocated MOH= 14.8*60= $888

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Spencer Chemical Corporation produces an oil-based chemical product which it sells to paint manufacturers. In 2019, the company
Snowcat [4.5K]

Answer:

Total incremental net income = $28,000

Incremental per gallon increase in net income = $0.70 per unit

Explanation:

a. The preparation of incremental statement to find out the increase in net income

Total production                                  $140,000

Less:

Incremental cost

Direct material              $68,000

($1.70 × 40,000 gallons)

Direct labor                  $24,000

($0.60 × 40,000 gallons)

Variable manufacturing

overhead                     $20,000

($0.50 × 40,000 gallons)

Total incremental cost                      ($112,000)

Total incremental net income          $28,000

b. Incremental per gallon increase in net income = Total incremental net income ÷ Total quantity

= $28,000 ÷ 40,000 gallons

= $0.70 per unit

Therefore the total incremental net income is $28,000 and incremental per gallon increase in net income is $0.70 per unit.

5 0
2 years ago
The Flores Family loves to go sailing on the weekends. Mr. Flores has decided to purchase a more spacious sailboat. The sailboat
zavuch27 [327]

Answer:

$367.86

Explanation:

To calculate this, we use the formula for calculating future value annuity (FVA) due as follows:

FV = M × {[(1 + r)^n - 1] ÷ r} × (1 + r) ................................. (1)

Where,

FV = Future value of an annuity or the cost of sailboat =  $20,000

M = Amount of each annuity  or to deposit monthly = ?

r = Monthly interest rate  = 0.06 ÷ 12 = 0.005

n = number of months = 4 years × 12 = 48

Substituting the values into equation (1), we have:

20,000 = M × {[(1 + 0.005)^48 - 1] ÷ 0.005} × (1 + 0.005)

20,000 = M × 54.3683213801713  

Making M the subject of the formula and solve, we have:

M = 20,000 ÷ 54.3683213801713  = $367.86

Therefore, Mr. Flores should deposit $367.86 in this account at the beginning of each month to be able to pay cash for the sailboat in 4 years.

8 0
2 years ago
When using the gzip utility, the option is also known as best compression and results in higher compression ratio?
Liula [17]
When it comes to using gzip, the vital thing that you need to remember is that this tool helps you in making your files smaller by compressing them. File types vary in how well they get compressed.

That's why there are recommendations given as to the best compression option for you to take. Though, it's not a must that that's the one you choose. In fact, you can run a simple gzip command to either get the minimum compression or get the maximum by varying the speed that it's run to compress the file.
5 0
2 years ago
Based on a predicted level of production and sales of 12,000 units, a company anticipates reporting operating income of $26,000
dexar [7]

Answer:

Fixed Cost = $10,000

Variable Costs = $90,000

Explanation:

Variable Cost per unit = $72,000 ÷ 12,000

                                      = $6

Variable Costs at 15,000 units = $6 x 15,000

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Fixed Cost (given) = $10,000

8 0
1 year ago
Pioneer Chicken advertises "lite" chicken with 30% fewer calories than standard chicken. When the process for "lite" chicken bre
zubka84 [21]

Answer:

LL = 420 -3\frac{25}{\sqrt{25}}= 405 represent the lower limit

UL = 420 +3\frac{25}{\sqrt{25}}= 435 represent the Upper limit

So then the limits for this case are (405, 435)

Explanation:

Let's define X as our random variable that represent the "number of calories for a chicken breast", and we have the following data:

\bar X = 420 , \sigma= 25

The select a sample of 25 chickens , n = 25. And we want to find the limits for a confidence interval within 3 deviations from the mean with z =3.

We assume that the distribution for X is normal. So then the distribution for the sample mean is also normal.

And for this case the confidence interval would be given by:

(\bar X -z\frac{\sigma}{\sqrt{n}} < \mu < \bar X -z\frac{\sigma}{\sqrt{n}})

So the limits are defined as:

LL = \bar X -z\frac{\sigma}{\sqrt{n}} represent the lower limit

UL = \bar X +z\frac{\sigma}{\sqrt{n}} represent the Upper limit

Since we have all the values given we cn replace like this:

LL = 420 -3\frac{25}{\sqrt{25}}= 405 represent the lower limit

UL = 420 +3\frac{25}{\sqrt{25}}= 435 represent the Upper limit

So then the limits for this case are (405, 435)

5 0
2 years ago
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