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exis [7]
2 years ago
8

Mohammed buys 31 cups of coffee each week. If a cup of coffee costs d dollars and Mohammed buys approximately the same number of

coffees every day, which would be a mathematical way to express the amount of money that Mohammed spends on coffee each day?
Mathematics
2 answers:
choli [55]2 years ago
5 0
Mohammed spends 31(d) on coffee each day
Advocard [28]2 years ago
5 0
31/7=4 4*d=amount spent a day on coffee
(7 for the days of the week)
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Consider coordinate system a, with the x axis along the plane. which forces lie along the axes?
Butoxors [25]
It seem like there are information missing on the question posted. Let me answer this question with all I know. So here is what I believe the answer is, the horizontal force.

Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
7 0
2 years ago
The National Center for Education Statistics would like to test the hypothesis that the proportion of Bachelor's degrees that we
agasfer [191]

This question involves the hypothesis test for the proportion. First we build the hypothesis, then find the test statistic, and according to the test statistic, we get the following answer:

The conclusion for this hypothesis test would be that because the absolute value of the test statistic is less than the critical value of 1.645, we do not reject the null hypothesis that the proportion of Bachelor's degrees that were earned by women equals 0.60.

The National Center for Education Statistics would like to test the hypothesis that the proportion of Bachelor's degrees that were earned by women equals 0.60

This means that at the null hypothesis, it is tested if the proportion is of 0.6, that is:

H_0: p = 0.6

At the alternative hypothesis, we test if the proportion is different of 0.6, that is:

H_1: p \neq 0.6

Decision rule:

Two-tailed test(test if the proportion is different of a value), so we exclude the top and bottom 0.1/2 = 0.05, meaning that looking at the z-table, we find a critical value of |Z_c| = 1.645, and the decision rule is:

Accept the null hypothesis: |Z| < 1.645

Reject the null hypothesis: |Z| > 1.645

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that \mu = 0.6, \sigma = 0.4

75 out of a sample of 140:

This means that:

n = 140, \pi = \frac{75}{140} = 0.5357

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5357 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{140}}}

z = -1.55

So |z| = 1.55

Decision:

The conclusion for this hypothesis test would be that because the absolute value of the test statistic is less than the critical value of 1.645, we do not reject the null hypothesis that the proportion of Bachelor's degrees that were earned by women equals 0.60.

For a similar example, you can check brainly.com/question/24166849

7 0
2 years ago
Given: Quadrilateral PQRS is a rectangle. Prove: PR = QS Reason Statement 1. Quadrilateral PQRS is a rectangle. given 2. Rectang
Alex73 [517]

Answer:

Step-by-step explanation:

Given:  Quadrilateral PQRS is a rectangle.

To prove: PR = QS

Proof: 1.  Quadrilateral PQRS is a rectangle(Given).

2. Rectangle PQRS is a parallelogram (Definition of a rectangle).

3. QP ≅ RS QR ≅ PS (Opposite angles of parallelogram are equal).

4. m∠QPS = m∠RSP = 90° (definition of a rectangle)

5. Δ PQS ≅ ΔSRP (SAS criterion for congruence)

6. PR ≅ QS (Corresponding sides of congruent triangles are congruent).

7. PR = QS (Congruent line segments have equal measures).

6 0
2 years ago
Read 2 more answers
Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b
horrorfan [7]

Answer:

a. X\sim N(\mu = 6.1, \sigma = 1.9) b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is z_{1} = (6.4-6.1)/1.9 = 0.1579 and the z-score related to 7 kg is z_{2} = (7-6.1)/1.9 = 0.4737, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0
2 years ago
If an exponential model was used to fit the data set below, which of the following would be the best prediction for the output o
satela [25.4K]

Answer:

The equation is found to be: y = 50.6e^{0.16x}

y(20) = 1241.34

Step-by-step explanation:

The given data is:

x:   3          7         11        14          17

y: 83      142      301     450      722

Now, we find sum summation values, relevant to the formula of exponential regression model, using calculator:

∑ ln y = 27.77305, ∑x ln y = 308.1494, ∑x = 52, ∑ x² = 664

and, n = no. of data points = 5

Now, we use formulae of exponential regression model to find out values of constant:

b = (n∑x lny - ∑x ∑ln y)/[n∑x² - (∑x)²]

b = [(5)(308.1494) - (52)(27.77305)]/[(5)(664) - (52)²]

b = 0.16

Now, for a;

a = (∑ln y - b∑x)/n

Therefore,

a = [(27.77305) - (0.16)(52)]/5

a = 3.9

For, α:

α = e^a = e^3.9

α = 50.6

So, the final equation of exponential regression model is given as:

y = \alpha e^{bx}\\ y = 50.6e^{0.16x}

Now, we find value of y for x = 20:

y(20) = (50.6) e^(0.16*20)

<u>y(20) = 1241.34</u>

8 0
2 years ago
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