Answer: Perceptual barriers
Explanation: As the name suggests perceptual barriers refers to the barriers that are created out from the perceptions. In such barriers the receiver did not even try to understand the message with all his efforts and behaves carelessly.
In the given case, the employees of Teresa did not understand the message and state that they do. Therefore, the employees might be acting carelessly or have some other perception about their boss.
They could have a perception that asking too much questions might affect their image in the eyes of boss.
Hence from the above we can conclude that the correct option is B.
Answer:
c. 12%; 15.7%
Explanation:
The computations are shown below:
For expected rate of return:
= (Weightage of risky asset × return of risky asset) + (Weightage of treasury bill × return of treasury bill)
= (0.70 × 0.15) + (0.30 × 0.05)
= 10.5% + 1.5%
= 12%
For standard deviation:
= Weightage of risky asset × (variance ^ half)
= 0.70 × (0.05 ^ 0.5)
= 15.7%
<span>I'm looking for a salary that can sustain my living situation. I don't want to drain your company of wealth or anything like that, but I don't want to be underpaid. You can look at all of my qualifications and we can agree on a salary that will be fair for both me and the company. For example, I think that a $100,000 a year salary is not one that is fair for the company, but I would not be opposed to it! $40,000 a year is probably fair for the company, but not for me. Somewhere in between those two values is a fair salary for me.</span>
<span>The AICPA rules would enforce that he is not allowed to join the board since he would be considered a firm professional. This would prevent a conflict of interest where he would serve as a director of a client. The AICPA is the American Institute of Certified Public Accountants.</span>
Answer:
no
Explanation:
H0: mean of sample=105
Ha: mean of sampe≠ 105
t-statistic= (population mean-sample mean)/(standard deviation/√sample size)
t-statistic= (105-103.3)/(16.3/√33)
t-statistic= 0.5991
degress of freedom= 32
for alpha 0.05, p-value from t-distributino table is 1.697
since t-statistic is less than the p-value, null hypothesis is accepted.
There is no sufficient evidence to conclude that the mean weight for non-top-20 starters is less than 105 the known value for top-20 teams
