Eye color in most mammals is dependent on the number of inherited pigment genes (melanin) that are additive in their effects. If
an uppercase letter contributes pigment but a lowercase does not, what would be expected in the progeny when a person with with genotype AaBB plans to procreate with genotype Aabb, The five possible colors are: Brown (4 pigment genes) > Hazel (3 pigment genes) > Green (2 pigment genes)> blue (1 pigment gene) > no pigment (absence of melanin is often seen as red).
1 answer:
Answer:
Hazel - 1/4 or 25%
Green - 1/2 or 50%
Blue - 1/4 or 25%
Explanation:
First, let us carry out the cross between AaBB and Aabb using a Punnet's square. The result is as below:
AABb - 4/16
AaBb - 8/16
aaBb - 4/16
(See the Punnet's square analysis in the attached image).
<em>AABb genotype has 3 pigments, hence, would be hazel.</em>
<em>AaBb genotype has 2 pigments, hence, would be green.</em>
<em>aaBb has one pigment, hence, would be blue.</em>
Expected progeny:
<em>Hazel - 1/4 or 25%</em>
<em>Green - 1/2 or 50%</em>
<em>Blue - 1/4 or 25%</em>
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Answer:
0%
Explanation:
It was a little hard to see your cross, so I made another one and it is attached below.
So what you are looking for is the likelihood of an offspring with a phenotype of brown spots and short tails.
Without using the Punnet, we can already deduce that it is 0%. This is because brown spots are recessive, and the only way a brown spotted dog would have this trait, is each parent had at least 1 recessive allele for this trait.
So the expected genotype for brown spot would be:
bb
Only one of them has this, so they cannot have brown spots.
