The Tangent Line Problem 1/3How do you find the slope of the tangent line to a function at a point Q when you only have that one point? This Demonstration shows that a secant line can be used to approximate the tangent line. The secant line PQ connects the point of tangency to another point P on the graph of the function. As the distance between the two points decreases, the secant line becomes closer to the tangent line.
Answer:
and
will be correct.
Explanation:
Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent, where, OM is congruent or equal to TS and
.
in quadrilaterals NPOM and VUTS-
since, the condition 
and, side UV=side OM follow for the above quadrilateral. (According to the figure)
then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.
similarly, these two conditions also follow in the case of
we can understand it by making the figures.
Answer:
y-intercept, c = 325
Slope, m = 50
The x-axis represents the number of months and y-axis represents the total amount in saving accounts.
Step-by-step explanation:
We are given the following in the question:
A saving account currently holds $325. Jesus adds $50 each month.
Let x be the number of months and y be the total money n the saving account.
Then, we can use a linear function to represent the money in the account.

Comparing to general linear function,

where m is the slope and tells the rate of change and c is the y-intercept that is the value when x is zero.
Comparing we get:
m = 50
c = 325
y-intercept = c = 325
Slope, m = 50
The x-axis represents the number of months and y-axis represents the total amount in saving accounts.
The attached image shows a graph for the same.
Answer:
Option D. (4, −1) and (−2, 6)
Step-by-step explanation:
we know that
The rule of the reflection of a point across the y-axis is equal to
(x,y) -----> (-x,y)
so
Applying the rule of the reflection
(−4, −1) -----> (4, −1)
(2, 6)----- (-2, 6)