Christian's car used 15 gallons to travel 270 miles. How far can he travel on 11 gallons?

32% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t

Lorico [155]

Answer:

A. 21.06%

B. 66.88%

C. 81.56%

Step-by-step explanation:

There are two possible answer for the question asked, yes(more likely to make purchases) or no. The probability for a random adults answer yes to the question is 32% so the probability that the adults answer no is 68%.

(a) exactly two

There is only one case for this question, 2 people say yes and 8 people say no. The calculation for this problem will be:

2P10 * P(yes)^2 * P(no)^8= 10!/2!8!* 32%^2 * 68%^8 = 0.21066= 21.06%

(b) more than two

There are a lot of case for more than two, its easier to find out the negation of the probability which is "two or less". Case that fulfill "two or less" will be: 2 yes and 8 no

1 yes and 9 no

0 yes and 10 no

The calculation for the negation will be:

~P(X)= 0P10 * P(yes)^0 * P(no)^10 + 1P10 * P(yes)^1 * P(no)^9 + 2P10 * P(yes)^2 * P(no)^8 =

10!/0!10!* 32%^0 * 68%^10 + 10!/1!9!* 32%^1 * 68%^9 + 10!/2!8!* 32%^2 * 68%^8

0.02113 + 0.09947 + 0.21066 = 0.33126= 33.12%

Since its the negation, you need to subtract 1 with the negation

P(X)= 1 - ~P(X)

P(X)= 1 - 33.12%= 66.88%

(c) between two and five, inclusive

Same formula as above, but the case is:

2 yes and 8 no

3 yes and 7 no

4 yes and 6 no

5 yes and 5 no

The calculation will be:

2P10 * P(yes)^2 * P(no)^8 + 3P10 * P(yes)^3 * P(no)^7 + 4P10 * P(yes)^4 * P(no)^6 + 5P10 * P(yes)^5 * P(no)^5 =

10!/2!8!* 32%^2 * 68%^8 + 10!/3!7!* 32%^3 * 68%^7 + 10!/4!6!* 32%^4 * 68%^6 + 10!/5!5!* 32%^5 * 68%^5

0.21066 + 0.26435 + 0.21770 + 0.1229= 0.81561= 81.56%

8 0

2 years ago

Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps

Firdavs [7]

ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the

x²y = -4 ... (I)

Condition 2: Real parts are the same

x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

x²y = -4 ... (I)
x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

y = -3 - x² ... (II)

Substituting into equation (I)

x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i

x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i

They result in conjugates

4 0

2 years ago

Read 2 more answers

.580 80 repeating as fraction

denis-greek [22]

First off, we'll move the non-repeating part in the decimal to the left-side, by doing a division by a power of 10.

then we'll equate the value to some variable, and move the repeating part over to the left as well.

anyhow, the idea being, we can just use that variable, say "x" for the repeating bit, let's proceed,

$\bf 0.580\overline{80}\implies \boxed{\cfrac{5.80\overline{80}}{10}}\qquad \textit{now, let's say }x= 5.80\overline{80}\\\\
-------------------------------$

$\bf thus\qquad \begin{array}{llll}
100\cdot x&=&580.80\overline{80}\\
&&575+5.80\overline{80}\\
&&575+x
\end{array}\qquad \implies 100x=575+x
\\\\\\
99x=575\implies x=\cfrac{575}{99}\qquad therefore\qquad \boxed{\cfrac{5.80\overline{80}}{10}}\implies \cfrac{\quad \frac{575}{99}\quad }{10}
\\\\\\
\cfrac{\quad \frac{575}{99}\quad }{\frac{10}{1}}\implies \cfrac{575}{99}\cdot \cfrac{1}{10}\implies \cfrac{575}{990}\implies \stackrel{simplified}{\cfrac{115}{198}}$

and you can check that in your calculator.

4 0

2 years ago

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Which of the following is a point of tangency on the circle below?<br> Help ASAP please

kumpel [21]

Answer:

Point B

Step-by-step explanation:

a point of tangency on a circle is where an outside line touches the outer circle at one point (the outside line touching it only once is what makes that line a tangent) so in this case the point of tangency is Point B

Please mark as Brainliest :)

6 0

2 years ago

Jaxon and Isaac live different directions from the city center. Jaxon lives 10 blocks east and 5 blocks north. Isaac lives 8 blo

givi [52]

Answer:

Step-by-step explanation:

As shown in the figure attached Jaxon is 10 blocks east and 5 blocks north.

So x-coordinates of Jaxon will be 10 units and y-coordinates will be 5 units.

and coordinates will be (10,5)

Similarly coordinates of Isaac will be defined by his distance towards west and distance towards south.

So x-coordinates will be 8 units and y-coordinates will be 15 units.

Therefore, coordinates of Isaac will be (-8,-15).

4 0

2 years ago

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