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marishachu [46]
2 years ago
14

A solution was prepared by dissolving 200.0 g of KCI in 215 g of water.

Chemistry
1 answer:
Archy [21]2 years ago
5 0

Answer:mole fraction of KCl = 0.18

Explanation:

no of moles of KCl     = Mass/Molar mass

where mass (weight) of KCl = 200.0g

molar mass of KC1= 74.6g/mol

                                                = 200/74.6   = 2.68 moles

no of moles of H2O = Mass/Molar mass

where mass (weight) of water = 215.0g

molar mass of water = 18.0g/mol

                                              = 215/18   = 11.94moles

mole fraction of KCl  = no of moles of KCl/(no of moles KCl + no of moles of H2O(water))

                                                = 2.68/(2.68+ 11.94)

                                                 = 2.68/14.62   = 0.18

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For the reaction below, Kp 5 1.16 at 800.8C. CaCO3(s) 34 CaO(s) 1 CO2(g) If a 20.0-g sample of CaCO3 is put into a 10.0-L contai
Elena L [17]

Answer:

The mass percentage of calcium carbonated reacted is 2.5%.

Explanation:

The reaction is:

CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Thus the Kp of the equilibrium will be:

Kp = partial pressure of carbon dioxide [as the other are solid]

Moles of calcium carbonate initially present = \frac{mass}{molarmass}=\frac{20}{100}=0.2

Let us apply ICE table to the equilibrium given:

                        CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Initial                       0.2                       0          0

Change                 -x                            +x        +x

Equilibrium           0.2-x                         x          x

Kp = partial pressure of carbon dioxide

Kp = Kc(RT)ⁿ

where n = difference in the number of moles of gaseous products and reactants

for given reaction n = 1

R = gas constant = 8.314 J /mol K

T = temperature = 800 ⁰C = 1073 K

Putting values

Kc =\frac{Kp}{RT}=\frac{1.16}{8.314X1073}=1.3X10^{-4}

Kc = \frac{[CO_{2}][CaO]}{[CaCO_{3}]}= \frac{x^{2} }{(0.2-x)}=1.3X10^{-4}

1.3X10^{-4}(0.2-x)=x^{2}

x^{2} = 0.26X10^{-4}-1.3X10^{-4}x

On calculating

x =  0.005

where x = the moles of calcium carbonate dissociated or reacted.

Percentage of the moles or mass reacted = \frac{molesreacted X100}{initialmoles}=\frac{0.005X100}{0.2}=2.5%

7 0
2 years ago
If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximat
Paladinen [302]

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c} where

v_r = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

\lambda_{rw} = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458} or v_r = 68518.7699 m/s or 68.52 km/s

8 0
2 years ago
Aluminum chlorohydrate, al2(oh)5cl, is an active ingredient in some antiperspirants. what is the mass percent of aluminum in thi
Flauer [41]
The percet of Al will be 100 times the mass of Al in the formula divided by the molar mass of the compound.

This table shows all the calculations involved

Compound: Al2 (OH)5 Cl

element     # of        atomic      mass in the          %
                  atoms    mass        formula
                                g/mol

Al              2             27             2*27 = 54 g        (54 / 174.5)*100 = 30.9%

O              5            16              5*16 = 80 g

H              5             1               5*1 =     5 g

Cl             1             35.5          1*35.5 = 35.5 g
                                              ----------------------
                   molar mass                      174.5 g

Answer: 30.9%
7 0
2 years ago
At the beginning of the school year, a chalk company receives an order for 2000 boxes which is the largest order ever placed. Ea
lys-0071 [83]

Answer:

  • <u>259,000 g of chalk.</u>

Explanation:

<u>1) Data:</u>

a) 2000 boxes

b) 175 g / box

c) % yield = 74%

<u>2) Formula: </u>

  • % yield = (theoretical yield / actual yield) × 100

<u>3) Solution:</u>

a) Calcualte the actual yield:

  • mass of product = 2000 box × 175 g/ box = 350,000 g

b) Solve for the theoretical yield from the % yield formula:

  • % yield = (theoretical yield / actual yield) × 100

        ⇒ theoretical yield = % yield × actual yield / 100

             theoretical yield = 74% × 350,000g / 100 = 259,000 g

6 0
2 years ago
Calculate the molarity of 0.207 grams of Ca(OH)2 in an aqueous solution with a total volume of 40.0 mL
STALIN [3.7K]

Answer:

40.0 mL. (4 marks)...

Explanation:

8 0
2 years ago
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