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Elis [28]
2 years ago
3

The glee club has $90 to spend on pens and pencils. Each pen costs $0.75 and each pencil costs $0.15. Let x represent the number

of pens, and
let y represent the number of pencils.
Part A

Select the equation that describes the number of club pens and pencils that the glee club can buy.
A. 0.15x + 0.75y = 90
OB. 0.75x+0.15y = 90
OC. 0.90(x + y) = 90
Part B

What is the greatest number of each type of writing tool that the club can buy?
greatest number of pens =
greatest number of pencils =
Mathematics
1 answer:
Nataly [62]2 years ago
3 0

Answer:

multiply it so you can get 90

Step-by-step explanation:

your going to multiply 0.75 times 15 or you can divied it to it is b

if you think im wrong press the heart

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20 points plz just help me. Explain how you would use fraction bars to find the quotient of StartFraction 10 Over 12 EndFraction
Katarina [22]

Answer:

5/4

Step-by-step explanation:

(10/12) / (4/6)

Reduce the fractions:

(5/6) / (2/3)

Multiply by the reciprocal:

(5/6) × (3/2)

15/12

Reduce:

5/4

7 0
2 years ago
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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
7nadin3 [17]

The equation of the cone should be z=\sqrt{x^2+y^2}. Parameterize S by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u\,\vec k

with 1\le u\le2 and 0\le v\le2\pi. Take the normal vector to S to be

\vec s_v\times\vec s_u=u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k

Then the integral of \vec F across S is

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_1^2(-u\cos v\,\vec\imath-u\sin v\,\vec\jmath+u^3\,\vec k)\cdot(u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_1^2(-u^2-u^4)\,\mathrm du\,\mathrm dv

=\displaystyle-2\pi\int_1^2(u^2+u^4)\,\mathrm du\,\mathrm dv=\boxed{-\frac{256\pi}{15}}

3 0
2 years ago
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n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p
Olenka [21]

Answer:

Conclusion

   There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

   The population mean for EBR is  \mu_ 1  = \$239,000

    The sample mean for Ascension parish  is \= x_2  = \$246,000

   The  p-value  is  p-value  =  0.045

     The level of significance is  \alpha = 0.01

The null hypothesis is  H_o : \mu_2  = \mu_1

The  alternative hypothesis is  H_a  :  \mu_2 > \mu_1

Here \mu_2 is the population mean for Ascension parish

   From the data given values we see that  

          p-value  >  \alpha

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

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2 years ago
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denis-greek [22]

Answer:

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5 0
2 years ago
After traveling for 4 hours and 1800 miles, an airplane begins a steady descent. When it begins descending, its altitude (height
andrey2020 [161]

Answer:

Part 1)  Descending Rate = -2,000 ft/min

Part 2)  Starting altitude value is 33,000 ft

Part 3)  The linear equation for the plane's altitude (y) as a function of time (x) is:  y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)  The information not used for the equation is that the plane was travelling for 4 hours to cover 1800 miles before starting the descent

Step-by-step explanation:

Part 1)

The rate at which the airplane descends is given by the difference between final and initial altitude (17,000 ft-33,000 ft) divided the elapsed time (8 minutes):

Descending\,\,Rate\,= \frac{17000-33000}{8} \,\,\frac{ft}{min}=\frac{-16000}{8} \,\,\frac{ft}{min}=-\,2000\,\,\frac{ft}{min}

Part 2)

When graphing the descent (that is the plane's altitude as a function of time), the starting value for the altitude should be 33,000 ft

Part 3)

We can build the equation of the plane's altitude as a function of time in slope y-intercept form y = m x + b

by noticing that the slope "m" stands for the rate of descent that we found in part 1), and then using the information that at time zero (when the plane starts its descent), its altitude is 33000 ft:

y=m\,x\,+\,b\\y=-2000\,\frac{ft}{min} \,x\,+\,b\\33000=-2000\,\frac{ft}{min} \,(0)\,+\,b\\33000=b

with this information about the intercept "b", we can write the final expression for the plane's altitude as a function of time during its descent as:

y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)

The information that was not used to write the descent equation was the initial details about how long the plane traveled (4 hours) and for 1800 miles.

5 0
2 years ago
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