Answer:
Patricia will run 132 kilometers with 11 liters of gas.
Step-by-step explanation:
The given table is representing the distance driven by Patricia for every liter of gas she puts in her car.
With 3 liters of gas she drives 36 kilometers.
This means in one liter of gas distance covered by the car = 
kilometers.
Similarly if the car runs 48 kilometers in 4 liters of gas then per liter distance covered by the gas will be = 
kilometers
Now with 11 liters of gas distance covered by the car will be = 11×12
= 132 kilometers
Therefore, with 11 liters of gas Patricia can run 132 kilometers.
Slope intercept form follows this general equation...
With this information you have posted, all you can do is find slope, your m. To calculate for slope, you need to use this following equation...
Then, you pick one of your coordinate pairs to be 1 and the other to be 2. I will choose the first coordinate pair as 1, so...
You plug in -1 into your slope formula...
Now, to find your y-intercept, or b, you must plug in one of your coordinate pairs. In that equation, you may plug in the values (3,3), so you'll have...
Just solve for b and you will be done
Check the first picture below.
now, the exercise states to get it from the graph, so we have to graph it first.
Check the second picture below.
recall, the height in feet is on the y-axis, and the time in seconds is on the x-axis.
and rounded up to the nearest tenth will be 0.6.
Answer:
7
Step-by-step explanation:
An equilateral triangle has a semiperimeter of 6 meters.
Heron’s formula: Area = StartRoot s (s minus a) (s minus b) (s minus c) EndRoot
An equilateral triangle has a semiperimeter of 6 meters. What is the area of the triangle? Round to the nearest square meter.
2 square meters
7 square meters
20 square meters
78 square meters
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
