Write and evaluate the expression. Then, check all that apply.
2 answers:
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Answer:
It is not possible to draw a triangle with given measurements of 3.5, 3.5, and 9.
Step-by-step explanation:
<em><u>Scalene Triangle</u></em> - All 3 sides have different lengths.
<em><u>I</u></em><em><u>s</u></em><em><u>osceles</u></em><em><u> </u></em><em><u>Triangle</u></em> - 2 sides have equal lengths.
<em><u>Equilateral</u></em><em><u> </u></em><em><u>Triangle</u></em> - All 3 sides have equal lengths.
You must be thinking that it would be Isosceles triangle, but it is not. The measurements you gave is 3.5, 3.5, and 9. Grab a piece of paper, ruler, and a pencil. First draw the length of 9 cm with your pencil and ruler (let us pretend that the measurements are in cm). Then draw 3.5 cm by placing your ruler on the end/start of your 9cm line that you drew before. Then, once again draw a 3.5 cm on the other end of the 9cm line. You will see something like the picture above. You can see that the two sides of the triangle are not intersecting on the top. This means that the triangle formation cannot be made by the given measurements of 3.5, 3.5, and 9.
I hope you understand my answer and this is an easy way to find if, from the given measurements, a triangle is able to be drawn. Thank you !!
Answer:
(A)
Step-by-step explanation:
Given the equations:
Substitution simply means replacing the variable y in the second equation with its equivalent x+3 from the first equation.
Substitution of y into gives us:
The correct option is A.
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to 
.
---> equation (1)
By using pythagoras rule which states that the
---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
substitute this value in equation (1) then
where A is the area of the square whose side is x
By using pythagoras rule which states that the
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
where A is the area of the square whose side is x