Full Question:
The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?
Answer:
the 11 the term is 5120
Step-by-step explanation:
Given
Geometry Progression
4th term = 40
10th term = 2560
Required
11 term.
The nth term of a geometric sequence is calculated as follows
Tₙ = arⁿ⁻¹
For the 4th term, n = 4 and Tₙ = 40
Substitute these in the given formula; this gives
40 = ar⁴⁻¹
40 = ar³. --;; equation 1
For the 10th term, n = 10 and Tₙ = 2560
Substitute these in the given formula; this gives
2560 = ar¹⁰⁻¹
2560 = ar⁹. --;; equation 2
Divide equation 2 by 1. This gives
2560/40 = ar⁹/ar³
64 = r⁹/r³
From laws of indices
64 = r⁹⁻³
64 = r⁶
Find 6th root of both sides
(64)^1/6 = r
r = (2⁶)^1/6
r = 2
Substitute r = 2 in equation 1
40 = ar³. Becomes
40 = a * 2³
40 = a * 8
40 = 8a
Divide both sides by 8
40/8 = 8a/8
5 = a
a = 5.
Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11
So,
Tₙ = arⁿ⁻¹ becomes
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹⁰
Tₙ = 5 * 1024
Tₙ = 5120.
Henxe, the 11 the term is 5120
By definition,
tanB = opposite/adjacent = 9/3 = 3
From the calculator,
B = arctan(3) = 71.6°
Answer: 72° (nearest degree)
Answer:
A. 251.2cm2
Step-by-step explanation:
Given radius of the cylinder 'r' = 2 cm
Given Height of the cylinder 'h' = 20 cm
Area of the curved surface = 2 π r h
The plastic coating would be needed to coat the surface of the chain link
A = 2 π r h
A = 2 × 3.14 ×2×20
A = 251.2 cm²
Conclusion:-
The plastic coating would be needed to coat the surface of the chain link
= 251.2 cm²
Answer:
Step-by-step explanation:
10+20+40=70
70*0.8=7*10*0.8=56 L (We Deliver)
total area =2*(10+20)*40+2*10*20=2*30*40+400=2400+400=2800 cm^2
2800*0.02=28*100*0.02=28*2=56 L (Go Parcels)
