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Georgia [21]
2 years ago
8

A cell phone company has a fixed cost of $1,500,000 per month and a variable cost of $20 per month per subscriber. The company c

harges $39.95 per month to its cell phone customers. (2.2) a. What is the breakeven point for this company? b. The company currently has 73,000 subscribers and proposes to raise its monthly fees to $49.95 to cover add-on features such as text messaging, song downloads, game playing, and video watching. What is the new breakeven point if the variable cost increases to $25 per customer per month? c. If 10,000 subscribers will drop their service because of the monthly fee increase in Part (b), will the company still be profitable?
Business
1 answer:
Lubov Fominskaja [6]2 years ago
4 0

Answer:

a. Break-even point = Fixed Cost divided by Contribution per unit

= $1,500,000/$19.95

= 75,188 subscribers

b. New break-even point = $1,500,000/$24.95

= 60,120 subscribers

c. Subscriber base = 73,000

less dropped subscribers 10,000

adjusted subscribers = 63,000

The company will still be profitable because it will break-even with 60,120 subscribers.  The excess 2,880 (63,000 - 60,120) subscribers after the break-even point of 60,120 will cause the company to make  some profit.

Explanation:

a) Data and Calculations:

Fixed cost = $1,500,000 per month

Variable cost $20 per month per subscriber

Charges to customers per month $39.95

Contribution = $39.95 - $20 = $19.95

New variable cost = $25

New monthly charge = $49.95

Contribution per unit = $49.95 - $25 = $24.95

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Answer:

$(94,179)

Explanation:

Particulars        Year 0               Year 1            Year 2

Cash flows     ($1,500,000)  A$1,000,000   A$2,000,000

DCF 14%              1                    0.8772         0.7695

Present Values 1500,000      A$877,200      A$ 1,538,935

Conversion           1                    0.55                      0.60

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The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
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Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

P(X=0)=(11C0)(0.5)^0 (1-0.5)^{11-0}=0.00049

P(X=1)=(11C0)(0.5)^1 (1-0.5)^{11-1}=0.0054

P(X=2)=(11C0)(0.5)^2 (1-0.5)^{11-2}=0.027

And adding we got:

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And replacing we got:

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And replacing we got:

P(X \leq 1)=0.00049 +0.0054= 0.0059

Explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest "number of women", on this case we now that:

X \sim Binom(n=11, p=0.5)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we want to find this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

P(X=0)=(11C0)(0.5)^0 (1-0.5)^{11-0}=0.00049

P(X=1)=(11C0)(0.5)^1 (1-0.5)^{11-1}=0.0054

P(X=2)=(11C0)(0.5)^2 (1-0.5)^{11-2}=0.027

And adding we got:

P(X \leq 2)= 0.033

Part b

For this case we want this probability:

P(X \geq 2)

And we can use the complement rule and we got:

P(X \geq 2)= 1-P(X

And replacing we got:

P(X \geq 2)= =1-[0.00049 +0.0054] = 0.994

Part c

For this case we want this probability:

P(X \leq 1)

And we can use the complement rule and we got:

P(X \leq 1)= 1-P(X

And replacing we got:

P(X \leq 1)=0.00049 +0.0054= 0.0059

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