May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
a.
x + y = 60
x = y + 30
b.
substitution:
(y + 30) = y = 60
2y + 30 = 60
2y = 30
y = 15
15 minutes for freehand
c.
No, because if he spends 40 minutes on the treadmill, he would have spent 10 minutes for freehand exercises. His total time in the gym would be 50 minutes, not 60.
Compatible numbers are those closest to these numbers- 65 rounded to the nearest tens is 70, and adding that to 150 we get B. 210.
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Hope this helps!
