If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?

2 answers:

4 0

May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x

1) If h(x) = 5x and k(x) = 1/x

Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)

2) If h(x) = 5 + x and k (x) = 1/x

Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]

stealth61 [152]2 years ago

4 0

Answer:

The answer is B!! 1/(5+x)

Step-by-step explanation:

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Benjamin decides to treat himself to breakfast at his favorite restaurant. He orders chocolate milk that costs \$3.25$3.25dollar

sdas [7]

Complete question:

Benjamin decides to treat himself to breakfast at his favorite restaurant. He orders chocolate milk that costs \$3.25$3.25dollar sign, 3, point, 25. Then, he wants to buy as many pancakes as he can, but he wants his bill to be at most \$30$30dollar sign, 30 before tax. The restaurant only sells pancakes in stacks of 444 pancakes for \$5.50$5.50dollar sign, 5, point, 50. Let SSS represent the number of stacks of pancakes that Benjamin buys. 1) Which inequality describes this scenario?

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Cost of chocolate milk = $3.25

Cost of pancakes = $5.50 (stack of 4)

Number of stacks of pancakes purchased = S

Maximum amount spent ≤ $30

Cost of chocolate + (Cost of pancake stack * number of stacks) ≤ $30

3.25 + 5.50S ≤ 30

5.50S ≤ 30 - 3.25

5.50S ≤ 26.75

S ≤ 26.75 / 5.50

S ≤ 4.86

Hence maximum number of pancake stacks he can purchase without exceeding budget = 4

Hence total number of pancakes = number of stacks * number in a stack

= 4 * 4

= 16

6 0

2 years ago

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The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 4 m

geniusboy [140]

We take the distance from points which indicates the location of the park and the mall.

For distance through north and east, we have positive values and negative for west and south.

Mall: (-3, -4)
Park: (3, 5)

The distance is calculate through the equation,
d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)

Substituting,
d = sqrt ((-4 - 5)² + (-3 - 3)²
d = sqrt 117 = 10.82
Thus, the distance between the mall and the park is approximately 10.82 miles.

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Darina [25.2K]

Answer:

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Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

$\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$